Science · Chemistry ★★★ Hard UNIT 9 OF 0

Nuclear Chemistry — Free Chemistry Review Games.

This unit covers radioactive decay, half-life and fission and fusion — essential concepts for Chemistry. Use our interactive study games to test your understanding, or review questions in traditional format below.

📋 60 questions ⏱ ~25 min
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Q1. What is radioactivity?
A A chemical reaction
B The spontaneous emission of particles or energy from an unstable nucleus
C Electricity from nuclear plants
D A type of chemical bond

Radioactivity is the spontaneous decay of unstable atomic nuclei, emitting radiation in the form of particles or energy.

Q2. What type of radiation is a helium nucleus?
A Beta particle
B Gamma ray
C Alpha particle
D Neutron

An alpha particle consists of 2 protons and 2 neutrons, identical to a helium-4 nucleus.

Q3. What is half-life?
A Half the life of an organism
B The time it takes for half of a radioactive sample to decay
C The energy of radiation
D Half the mass of an atom

Half-life is the time required for half the atoms in a radioactive sample to undergo decay.

Q4. Which type of radiation has the highest penetrating power?
A Alpha
B Beta
C Gamma
D All are equal

Gamma rays are high-energy electromagnetic radiation with the greatest penetrating power, requiring thick lead or concrete to stop.

Q5. What is nuclear fission?
A Combining small nuclei
B Splitting a large nucleus into smaller ones
C Electron capture
D Chemical decomposition

Nuclear fission is the splitting of a heavy nucleus into two lighter nuclei, releasing enormous energy.

Q6. What is nuclear fusion?
A Splitting atoms apart
B Combining light nuclei to form a heavier nucleus, releasing energy
C A chemical reaction
D Radioactive decay

Nuclear fusion joins light nuclei (like hydrogen) to form heavier ones, releasing energy as in the Sun.

Q7. If a radioactive sample has a half-life of 10 years, how much remains after 30 years?
A 1/2
B 1/4
C 1/8
D 1/16

After 3 half-lives (30 years), the fraction remaining is (1/2)^3 = 1/8 of the original sample.

Q8. What is a beta particle?
A A proton
B A high-energy electron or positron emitted from a nucleus
C A neutron
D A photon

A beta particle is a high-energy electron (beta-minus) or positron (beta-plus) emitted during radioactive decay.

Q9. What element is commonly used as fuel in nuclear power plants?
A Carbon
B Uranium
C Iron
D Gold

Uranium-235 is the primary fuel in most nuclear power plants because it readily undergoes fission.

Q10. What is transmutation?
A A chemical reaction
B The conversion of one element into another through nuclear reactions
C Dissolving a solid
D Changing states of matter

Transmutation is the changing of one element into another by altering the number of protons in the nucleus through nuclear reactions.

Q11. What is the relationship between mass and energy in nuclear reactions?
A Mass is always conserved exactly
B A small amount of mass is converted to a large amount of energy according to E = mc^2
C Energy is converted to mass
D There is no relationship

Einstein's equation E = mc^2 shows that mass can be converted to energy; the small mass defect in nuclear reactions produces enormous energy.

Q12. What is the mass defect?
A A manufacturing error
B The difference between the mass of separated nucleons and the actual mass of the nucleus
C The mass of an electron
D A measurement uncertainty

The mass defect is the 'missing' mass that has been converted to binding energy holding the nucleus together.

Q13. Why is carbon-14 dating limited to objects less than about 50,000 years old?
A Carbon-14 does not exist in older objects
B After about 10 half-lives (5,730 years each), too little C-14 remains to measure accurately
C Carbon-14 is not radioactive
D Older objects have no carbon

Carbon-14 has a half-life of 5,730 years; after ~50,000 years (~9 half-lives), the remaining C-14 is too small to detect reliably.

Q14. What is a chain reaction in nuclear fission?
A A series of chemical reactions
B One fission event releases neutrons that trigger more fissions in a self-sustaining process
C Electrons bouncing between atoms
D A type of fusion

In a chain reaction, neutrons from one fission event cause additional atoms to split, each releasing more neutrons in a self-sustaining cascade.

Q15. Why is nuclear fusion more difficult to achieve on Earth than fission?
A Fusion produces less energy
B Extremely high temperatures and pressures are needed to overcome electrostatic repulsion between nuclei
C Fusion does not work on Earth
D Fission requires higher temperatures

Fusion requires temperatures of millions of degrees to overcome the electrostatic repulsion between positively charged nuclei, making containment extremely challenging.

Q16. What is an alpha particle composed of?
A Two protons and two neutrons
B Two protons and two electrons
C One proton and one neutron
D Four neutrons

An alpha particle is identical to a helium-4 nucleus, held together by the strong nuclear force, and consists of two protons and two neutrons with no electrons. The choice "Two protons and two electrons" is wrong because electrons are not found in the nucleus and would give the particle a different charge. Students should remember that alpha particles carry a \(+2\) charge and a mass number of 4, which explains their strong ionizing ability.

Q17. What is a gamma ray?
A High-energy electromagnetic radiation emitted from an unstable nucleus
B A stream of helium nuclei
C A stream of high-speed electrons
D A burst of neutrons

Gamma rays are photons of electromagnetic radiation released when a nucleus relaxes from an excited energy state to a lower one, so they have no mass or charge. "A stream of helium nuclei" describes alpha particles instead, which are massive charged particles, not photons. On the exam, remember that gamma emission usually accompanies alpha or beta decay as the nucleus sheds excess energy rather than changing its composition.

Q18. What happens to the atomic number of a nucleus during alpha decay?
A It decreases by 2
B It increases by 2
C It stays the same
D It decreases by 4

Alpha decay ejects two protons along with two neutrons, so the atomic number (proton count) of the parent nucleus decreases by 2. "It stays the same" is incorrect because alpha decay always transmutes the element by removing protons, unlike gamma decay which leaves the atomic number unchanged. A key rule to carry forward is that alpha decay changes both the atomic number and mass number, transforming the element into a new one.

Q19. What happens to the mass number of a nucleus during beta-minus decay?
A It stays the same
B It decreases by 1
C It increases by 1
D It decreases by 4

In beta-minus decay, a neutron converts into a proton and an emitted electron, so the total number of nucleons (mass number) does not change even though the atomic number increases by 1. "It decreases by 1" is wrong because no nucleon is lost, only a neutron is transformed into a proton internally. Remember that beta decay changes the identity of the element by altering the proton count while conserving the mass number.

Q20. What is a positron?
A The antiparticle of the electron, with positive charge and equal mass
B A particle identical to a proton
C A neutral particle emitted during alpha decay
D A high-energy photon

A positron is the antimatter counterpart of an electron, carrying a \(+1\) charge but the same tiny mass as an electron, and it is emitted when a proton converts into a neutron in positron emission. "A particle identical to a proton" is wrong because a proton has far greater mass and is not an antiparticle. Students should link positron emission to proton-rich nuclei seeking stability by lowering their atomic number.

Q21. What occurs during electron capture?
A An inner-shell electron combines with a proton in the nucleus to form a neutron
B An electron is ejected from the nucleus
C A proton is converted into a positron
D A neutron splits into a proton and electron

In electron capture, the nucleus absorbs a nearby inner-shell electron, which combines with a proton to produce a neutron and a neutrino, lowering the atomic number by 1. "An electron is ejected from the nucleus" is incorrect because electron capture involves absorption, not emission, of an electron. This process is another pathway, alongside positron emission, for proton-rich nuclei to move toward the band of stability.

Q22. What term describes a specific atomic species defined by its exact number of protons and neutrons?
A Nuclide
B Isotope only
C Isobar
D Allotrope

A nuclide refers to any distinct atomic nucleus characterized by a specific number of protons and neutrons, making it the general term used to label a particular species like carbon-14 or uranium-238. "Isobar" is incorrect because isobars are nuclides with the same mass number but different atomic numbers, not a general term for any nuclide. Recognizing the term nuclide helps clarify nuclear equations, which always balance mass numbers and atomic numbers between nuclides.

Q23. What is the charge of a beta-minus particle?
A \(-1\)
B \(+1\)
C \(0\)
D \(+2\)

A beta-minus particle is a fast-moving electron ejected from the nucleus, so it carries a charge of \(-1\), matching the charge of an ordinary electron. The choice "\(+2\)" describes an alpha particle's charge instead, which comes from its two protons. Remembering the charges of alpha (\(+2\)), beta (\(-1\) or \(+1\) for positrons), and gamma (\(0\)) radiation is essential for predicting deflection in electric or magnetic fields.

Q24. What is meant by "critical mass" in nuclear fission?
A The minimum amount of fissile material needed to sustain a chain reaction
B The maximum mass a nucleus can have before it decays
C The mass lost during a fission reaction
D The mass of neutrons required to start fission

Critical mass is the smallest quantity of fissile material, such as uranium-235, needed so that enough neutrons are captured to keep the chain reaction self-sustaining rather than dying out. "The mass lost during a fission reaction" instead describes the mass defect, a separate concept related to energy release, not reaction sustainability. Understanding critical mass is essential for explaining why reactors and weapons require a certain minimum quantity and geometry of fuel.

Q25. What is the purpose of a moderator in a nuclear fission reactor?
A To slow down fast neutrons so they can be captured more efficiently by fuel nuclei
B To absorb excess neutrons and stop the reaction
C To cool the reactor core directly through fusion
D To convert alpha particles into gamma rays

A moderator, such as water or graphite, slows fast neutrons produced by fission into slower thermal neutrons, which are much more likely to be captured by fuel nuclei like uranium-235 and trigger further fission. "To absorb excess neutrons and stop the reaction" instead describes the role of control rods, which regulate rather than sustain the reaction. Distinguishing moderators from control rods is a common point of confusion that is worth memorizing for reactor-design questions.

Q26. What process provides the Sun's energy?
A Nuclear fusion of hydrogen into helium
B Nuclear fission of uranium
C Chemical combustion of hydrogen gas
D Radioactive decay of heavy elements

The Sun generates energy through nuclear fusion, in which hydrogen nuclei combine under extreme temperature and pressure to form helium, releasing enormous energy according to \(E=mc^2\). "Chemical combustion of hydrogen gas" is incorrect because combustion involves rearranging electron bonds, not nuclear reactions, and could not sustain the Sun's output for billions of years. Recognize that stellar energy is a real-world example illustrating how fusion converts a small amount of mass into a large amount of energy.

Q27. Which unit is commonly used to measure the rate of radioactive decay (activity) of a sample?
A Becquerel
B Joule
C Mole
D Watt

The becquerel (Bq) measures activity as the number of nuclear disintegrations occurring per second in a sample, making it the standard SI unit for radioactive decay rate. "Joule" instead measures energy, which is a different physical quantity related to but distinct from decay rate. Knowing that activity units like becquerel or curie describe decay events per unit time helps distinguish decay rate from energy release or half-life.

Q28. What is a radioactive decay series?
A A sequence of successive decays in which an unstable nucleus transforms through several daughter nuclides until a stable nuclide is reached
B A single decay event that produces a stable isotope directly
C The list of all isotopes of one element
D A chart ranking isotopes by half-life length

A decay series is a chain of consecutive radioactive decays, such as alpha and beta emissions, that a heavy unstable nucleus undergoes step by step until it finally reaches a stable, non-radioactive nuclide. "A single decay event that produces a stable isotope directly" is wrong because many heavy nuclides like uranium-238 require over a dozen intermediate decays before reaching stability. This concept explains why natural samples of uranium ore contain many other radioactive elements as intermediate decay products.

Q29. Uranium-238 undergoes alpha decay. What is the resulting daughter nuclide?
A \(^{234}_{90}Th\)
B \(^{234}_{92}U\)
C \(^{238}_{90}Th\)
D \(^{242}_{94}Pu\)

Alpha decay removes 2 protons and 2 neutrons, so uranium-238 (\(Z=92\), \(A=238\)) becomes a nuclide with \(Z=90\) and \(A=234\), which is thorium-234, matching \(^{234}_{90}Th\). The option \(^{238}_{90}Th\) is wrong because it keeps the original mass number unchanged, which contradicts the loss of 4 nucleons in alpha decay. Balancing both mass number and atomic number is the essential skill for writing any correct nuclear decay equation.

Q30. Carbon-14 undergoes beta-minus decay to form which nuclide?
A \(^{14}_{7}N\)
B \(^{14}_{5}B\)
C \(^{13}_{6}C\)
D \(^{14}_{8}O\)

In beta-minus decay, a neutron converts to a proton, so carbon-14 (\(Z=6\)) gains one proton to become nitrogen-14 (\(Z=7\)) while the mass number stays at 14, giving \(^{14}_{7}N\). The option \(^{13}_{6}C\) is wrong because beta decay does not change the mass number, only the atomic number. This reaction is the basis of carbon-14 dating, since the decay of carbon-14 into nitrogen-14 occurs at a known, constant rate.

Q31. A sample contains \(80\,g\) of a radioactive isotope. After 3 half-lives, how much of the isotope remains?
A \(10\,g\)
B \(20\,g\)
C \(40\,g\)
D \(6.67\,g\)

Each half-life reduces the remaining amount by half, so after three half-lives the mass follows \(80 \to 40 \to 20 \to 10\), leaving \(10\,g\). The choice "\(6.67\,g\)" incorrectly divides the original mass by 3 instead of by \(2^3=8\), treating decay as linear rather than exponential. Always remember that radioactive decay is exponential, so the remaining amount is found using \(N = N_0(1/2)^n\) for \(n\) half-lives.

Q32. A radioisotope has a half-life of \(5\) years. How many years are required for a sample to decay to \(\frac{1}{8}\) of its original amount?
A \(15\) years
B \(10\) years
C \(20\) years
D \(40\) years

Since \(\frac{1}{8} = \left(\frac{1}{2}\right)^3\), the sample must undergo 3 half-lives, and with each half-life lasting \(5\) years, the total time is \(3 \times 5 = 15\) years. The choice "\(10\) years" corresponds to only 2 half-lives, which would leave \(\frac{1}{4}\) of the sample, not \(\frac{1}{8}\). When solving these problems, first express the remaining fraction as a power of \(\frac{1}{2}\) to identify the number of half-lives elapsed.

Q33. Which material is typically required to fully block gamma radiation?
A Thick lead or concrete
B A sheet of paper
C A few millimeters of aluminum
D Human skin

Gamma rays are highly penetrating, uncharged electromagnetic radiation, so stopping them requires dense, thick shielding such as several centimeters of lead or a substantial layer of concrete. "A sheet of paper" is sufficient only to stop alpha particles, which are large, charged, and easily absorbed by thin materials. Ranking shielding needs from paper (alpha) to aluminum (beta) to lead or concrete (gamma) is a key comparison for radiation safety questions.

Q34. Why do alpha particles have high ionizing power despite low penetrating power?
A Their large mass and charge cause frequent interactions with matter over a short distance
B They travel at the speed of light and pass through matter quickly
C They carry no charge, so they interact weakly with atoms
D They are electromagnetic waves that pass through matter

Alpha particles are relatively large and carry a \(+2\) charge, so they interact strongly and frequently with atoms in their path, stripping electrons rapidly but losing energy and stopping within a very short distance. "They carry no charge, so they interact weakly with atoms" is incorrect and actually describes gamma rays and neutrons, not alpha particles, which are strongly charged. This inverse relationship between ionizing power and penetrating depth is a recurring theme when comparing alpha, beta, and gamma radiation.

Q35. Nuclei with too high a neutron-to-proton ratio tend to undergo which type of decay to move toward stability?
A Beta-minus decay
B Alpha decay
C Positron emission
D Electron capture

Beta-minus decay converts a neutron into a proton, lowering the neutron-to-proton ratio and moving a neutron-rich nucleus closer to the band of stability. "Positron emission" instead lowers the proton count and is used by proton-rich nuclei, the opposite situation described in the question. Predicting the correct decay mode from a nucleus's position relative to the band of stability is a core skill in nuclear chemistry.

Q36. How does nuclear fission fundamentally differ from nuclear fusion?
A Fission splits a heavy nucleus into smaller nuclei, while fusion combines light nuclei into a heavier one
B Fission combines light nuclei, while fusion splits heavy nuclei
C Fission only occurs in stars, while fusion occurs in reactors
D Fission releases no energy, while fusion releases large amounts of energy

Fission is the splitting of a large, heavy nucleus such as uranium-235 into smaller fragments, while fusion is the joining of small, light nuclei such as hydrogen isotopes into a larger nucleus, and both processes release energy. "Fission only occurs in stars, while fusion occurs in reactors" reverses reality, since fusion powers stars and fission is used in human-made reactors. Both processes release energy because they move nuclei toward higher binding energy per nucleon, just from opposite ends of the mass spectrum.

Q37. What is the function of control rods in a fission reactor?
A They absorb excess neutrons to regulate the rate of the chain reaction
B They slow down neutrons to increase fission probability
C They provide the fuel for the chain reaction
D They convert heat into electricity directly

Control rods, often made of materials like boron or cadmium that readily absorb neutrons, are inserted or withdrawn from the reactor core to control the number of neutrons available for further fission, keeping the chain reaction stable. "They slow down neutrons to increase fission probability" describes the moderator's role instead, which is a separate reactor component. Control rods and moderators serve opposite regulatory purposes and are frequently confused on exams.

Q38. Why is carbon-14 useful for dating materials that were once part of living organisms?
A Living organisms continuously exchange carbon with their environment, fixing a known starting ratio of carbon-14 to carbon-12
B Carbon-14 is present only in inorganic minerals
C Carbon-14 has an extremely long half-life suited to dating ancient rocks
D Carbon-14 does not decay while an organism is alive

While alive, organisms continuously take in carbon through respiration or diet, maintaining a roughly constant ratio of carbon-14 to carbon-12 matching the atmosphere, and after death that ratio changes at a known decay rate, allowing scientists to calculate elapsed time. "Carbon-14 has an extremely long half-life suited to dating ancient rocks" is false because carbon-14's half-life of about 5,730 years is actually relatively short, better suited to recent organic material rather than geologic timescales. This principle of a known, constant intake ratio followed by predictable decay after death is the foundation of all radiometric organic dating.

Q39. As a radioactive sample decays over time, what happens to its activity?
A It decreases exponentially, following the same pattern as the remaining mass
B It remains constant regardless of the amount remaining
C It increases as fewer atoms remain
D It decreases linearly with time

Activity is directly proportional to the number of undecayed atoms present, so as the number of atoms decreases exponentially over successive half-lives, the sample's activity decreases in the same exponential pattern. "It decreases linearly with time" is incorrect because radioactive decay follows an exponential curve, not a straight-line relationship. Recognizing that activity and remaining quantity always track together exponentially is key to interpreting decay graphs.

Q40. What is a key medical application of radioactive tracers?
A Emitting detectable radiation from inside the body to image organ function without invasive surgery
B Providing structural support in artificial joints
C Sterilizing surgical instruments through fission
D Replacing chemotherapy entirely in cancer treatment

Radioactive tracers are introduced into the body and their emitted radiation is detected externally, allowing physicians to visualize processes such as blood flow or organ function without surgery. "Providing structural support in artificial joints" describes a mechanical, non-radioactive application unrelated to tracer imaging. This use of radioisotopes highlights how controlled, low-dose radiation can be applied for diagnostic rather than destructive purposes.

Q41. How does the half-life of a radioactive isotope change if the sample size is doubled?
A It stays the same, because half-life is independent of the amount of substance present
B It doubles, because there are twice as many atoms to decay
C It is cut in half, because more atoms increase collision frequency
D It becomes unpredictable, since decay is a random process

Half-life is a fixed statistical property of a particular isotope's nucleus and does not depend on the quantity of material present, so doubling the sample size leaves the half-life unchanged even though more total decay events occur. "It doubles, because there are twice as many atoms to decay" confuses total activity with half-life, which are related but distinct quantities. This independence of half-life from sample size is a fundamental property that distinguishes nuclear decay from chemical reaction rates.

Q42. What are "fission fragments"?
A The smaller, often radioactive nuclei produced when a heavy nucleus splits apart
B The neutrons released during a fission reaction
C The gamma rays emitted after fission occurs
D The leftover fuel rods after a chain reaction ends

When a heavy nucleus like uranium-235 splits during fission, it produces two or more smaller nuclei called fission fragments, which are often unstable and undergo further radioactive decay. "The neutrons released during a fission reaction" describes a separate product of fission used to sustain the chain reaction, not the daughter nuclei themselves. Fission fragments are a major source of nuclear waste because many of them remain radioactive for long periods.

Q43. What extreme conditions are required to initiate nuclear fusion?
A Very high temperature and pressure to overcome electrostatic repulsion between nuclei
B Low temperature and low pressure to slow nuclei enough to collide
C A strong magnetic field alone, with no temperature requirement
D The presence of a moderator such as graphite

Fusion requires extremely high temperatures and pressures to give nuclei enough kinetic energy to overcome their mutual electrostatic repulsion and get close enough for the strong nuclear force to bind them together. "A strong magnetic field alone, with no temperature requirement" is incorrect because magnetic confinement only helps contain plasma, it does not replace the need for extreme thermal energy. This requirement for extreme conditions explains why controlled fusion power remains far more difficult to sustain on Earth than fission.

Q44. The half-life of an isotope is related to its decay constant \(\lambda\) by which expression?
A \(t_{1/2} = \frac{0.693}{\lambda}\)
B \(t_{1/2} = 0.693\lambda\)
C \(t_{1/2} = \lambda^2\)
D \(t_{1/2} = \frac{\lambda}{0.693}\)

The relationship \(t_{1/2} = \frac{0.693}{\lambda}\) comes from solving the exponential decay equation for the time at which half the original atoms remain, where \(0.693 \approx \ln 2\). The option \(t_{1/2} = 0.693\lambda\) incorrectly multiplies rather than divides, which would make half-life increase with a larger decay constant, contradicting the physical relationship. Isotopes with a larger decay constant \(\lambda\) decay faster and therefore have a shorter half-life, an inverse relationship worth memorizing.

Q45. Compared to a fission reaction, a fusion reaction involving the same mass of reactants generally releases...
A Significantly more energy per unit mass
B Significantly less energy per unit mass
C About the same amount of energy
D No energy, since fusion requires energy input only

Fusion reactions convert a larger fraction of mass into energy per nucleon than fission does, because light nuclei gain much more binding energy per nucleon when they combine than heavy nuclei gain when they split, making fusion more energy-dense per unit mass. "About the same amount of energy" is incorrect because comparisons of energy output per gram of fuel show fusion, such as hydrogen fusion in stars, vastly outproducing fission. This higher energy density is why fusion is considered a highly attractive but technically challenging future energy source.

Q46. What distinguishes a breeder reactor from a conventional fission reactor?
A It produces more fissile material than it consumes by converting non-fissile isotopes into fissile ones
B It uses fusion instead of fission to generate power
C It cannot sustain a chain reaction without external neutron sources
D It uses water instead of uranium as fuel

A breeder reactor is designed so that excess neutrons convert non-fissile isotopes, such as uranium-238, into new fissile material like plutonium-239, allowing it to generate more usable fuel than it consumes. "It uses fusion instead of fission to generate power" is incorrect because breeder reactors still rely on fission chain reactions, just with an additional fuel-breeding process built in. This ability to extend fuel supplies makes breeder reactors an important, though controversial, concept in nuclear energy planning.

Q47. Which isotope is commonly used as the alpha-emitting source in household smoke detectors?
A Americium-241
B Uranium-238
C Carbon-14
D Cobalt-60

Americium-241 emits a steady, low-level stream of alpha particles that ionize air inside the detector, and smoke disrupting this ionized air path triggers the alarm circuit. "Cobalt-60" instead is a strong gamma emitter used in medical sterilization and cancer treatment, not household smoke detectors. This application shows how the controlled, small-scale use of alpha radiation can be safe and practical in everyday devices, since alpha particles cannot penetrate the detector's casing.

Q48. A radioactive sample decays from \(160\,g\) to \(20\,g\). If the half-life is \(4\) years, how many years have passed?
A \(12\) years
B \(8\) years
C \(16\) years
D \(20\) years

Since \(160 \to 80 \to 40 \to 20\) represents three successive halvings, three half-lives have elapsed, and with each half-life lasting \(4\) years, the total elapsed time is \(3 \times 4 = 12\) years. The choice "\(16\) years" would correspond to four half-lives, which would leave only \(10\,g\), not \(20\,g\). Solving these problems requires carefully counting how many times the sample was halved before matching the final given mass.

Q49. Uranium-235 captures a neutron and undergoes fission, producing barium-141, three neutrons, and one other nuclide. What is that nuclide?
A \(^{92}_{36}Kr\)
B \(^{92}_{38}Sr\)
C \(^{89}_{36}Kr\)
D \(^{94}_{36}Kr\)

Conserving mass number gives \(235+1 = 141 + 3 + A\), so \(A=92\), and conserving atomic number gives \(92 = 56 + Z\), so \(Z=36\), identifying the unknown nuclide as krypton-92, or \(^{92}_{36}Kr\). The choice \(^{92}_{38}Sr\) has the correct mass number but the wrong atomic number, which would violate conservation of protons in the reaction. Every nuclear equation, including fission reactions, must balance both total mass number and total atomic number on each side.

Q50. Why does nuclear fusion release more energy per nucleon than nuclear fission?
A Light nuclei sit farther from the peak of the binding energy curve, so fusing them into medium-mass nuclei releases a larger increase in binding energy per nucleon than splitting heavy nuclei does
B Fusion reactions convert protons directly into neutrons, releasing extra mass as energy
C Fission reactions require external energy input, while fusion reactions do not
D Heavy nuclei have no binding energy, so all their mass converts to energy upon splitting

On the binding-energy-per-nucleon curve, light elements like hydrogen start far below the peak near iron, so combining them into medium-mass nuclei produces a steep rise in binding energy per nucleon and a correspondingly large energy release, larger than the more modest rise heavy nuclei experience when splitting toward the peak. "Fission reactions require external energy input, while fusion reactions do not" is false because both reactions are exothermic once initiated, though fusion requires extreme conditions to begin. Understanding the shape of the binding energy curve explains why both fission and fusion release energy, but why fusion is inherently more energy-dense per nucleon.

Q51. A radioactive sample decays to \(\frac{1}{32}\) of its original activity. How many half-lives have elapsed?
A 5
B 4
C 6
D 32

Since \(\left(\frac{1}{2}\right)^5 = \frac{1}{32}\), exactly 5 half-lives must have passed for the activity to drop to that fraction of its original value. The choice "32" mistakes the denominator of the fraction for the number of half-lives, rather than recognizing it as \(2^5\). Converting a decay fraction into a power of \(\frac{1}{2}\) is the essential first step in solving half-life word problems.

Q52. A fossil contains \(12.5\%\) of its original carbon-14. Given carbon-14's half-life of about \(5730\) years, approximately how old is the fossil?
A \(17{,}190\) years
B \(11{,}460\) years
C \(22{,}920\) years
D \(5{,}730\) years

Since \(12.5\% = \frac{1}{8} = \left(\frac{1}{2}\right)^3\), the fossil has undergone 3 half-lives, so its age is approximately \(3 \times 5730 \approx 17{,}190\) years. The choice "\(11{,}460\) years" corresponds to only 2 half-lives, which would leave \(25\%\) of the carbon-14, not \(12.5\%\). Radiometric age problems always require converting the remaining percentage into the correct number of half-lives before multiplying by the half-life duration.

Q53. In a fission reactor, what does the term "neutron multiplication factor" (\(k\)) describe, and what value of \(k\) indicates a sustained, steady chain reaction?
A The ratio of neutrons in one generation to the previous generation; \(k=1\) indicates a steady, self-sustaining reaction
B The number of neutrons absorbed by control rods; \(k=1\) indicates the reactor has shut down
C The ratio of protons to neutrons in the fuel; \(k=1\) indicates maximum instability
D The energy released per fission event; \(k=1\) indicates minimal energy output

The neutron multiplication factor \(k\) compares the number of neutrons produced in one fission generation to the number produced in the previous generation, and when \(k=1\) the reaction proceeds at a constant, controllable rate, called criticality. "The number of neutrons absorbed by control rods; \(k=1\) indicates the reactor has shut down" incorrectly links \(k=1\) to shutdown, when in fact \(k<1\) (subcritical) corresponds to a dying reaction and \(k>1\) (supercritical) corresponds to an escalating one. Reactor operators continuously adjust control rods to keep \(k\) as close to 1 as possible for stable power output.

Q54. Two isotopes, X and Y, start with equal numbers of atoms. Isotope X has a shorter half-life than isotope Y. Which statement about their initial activities is correct?
A Isotope X has a higher initial activity because activity is inversely proportional to half-life for a fixed number of atoms
B Isotope X has a lower initial activity because it decays faster
C Both isotopes have identical initial activity regardless of half-life
D Isotope Y has a higher initial activity because it decays faster

Activity is given by \(A = \lambda N\), and since \(\lambda = \frac{0.693}{t_{1/2}}\), a shorter half-life corresponds to a larger decay constant and thus a higher activity for the same number of atoms \(N\), meaning isotope X decays faster and shows higher initial activity. "Both isotopes have identical initial activity regardless of half-life" ignores the direct dependence of decay rate on the decay constant, which differs between isotopes with different half-lives. This inverse relationship between half-life and activity is essential for comparing radioactive sources with the same atom count but different stabilities.

Q55. A nucleus has a calculated mass defect of \(\Delta m\). Which equation correctly relates this mass defect to the binding energy released, \(E_b\)?
A \(E_b = \Delta m \, c^2\)
B \(E_b = \frac{\Delta m}{c^2}\)
C \(E_b = \Delta m \cdot c\)
D \(E_b = \frac{c^2}{\Delta m}\)

Einstein's mass-energy equivalence relation \(E = mc^2\) applies directly to nuclear binding energy, so the energy released when nucleons bind together equals the mass defect multiplied by the speed of light squared, giving \(E_b = \Delta m \, c^2\). The choice \(E_b = \frac{\Delta m}{c^2}\) inverts the relationship and would produce physically inconsistent, extremely tiny energy values that do not match observed nuclear binding energies. This equation is the mathematical backbone connecting mass defect calculations to the enormous energy released in fission and fusion reactions.

Q56. Along the curve of binding energy per nucleon versus mass number, which region corresponds to the most stable nuclei?
A The peak near iron-56, where nuclei have the highest binding energy per nucleon
B The far right, corresponding to the heaviest elements like uranium
C The far left, corresponding to hydrogen and helium
D There is no relationship between binding energy per nucleon and stability

The binding energy per nucleon curve rises sharply from light elements, peaks near iron-56, and then gradually declines for heavier elements, meaning nuclei near iron-56 are held together most tightly per nucleon and are the most stable overall. "The far right, corresponding to the heaviest elements like uranium" is incorrect because heavy elements sit on the declining side of the curve, which is why they can release energy through fission. This curve is the central tool for predicting whether fission or fusion will release energy for a given nucleus.

Q57. Why can heavy nuclei like uranium-235 release energy through fission, while iron-56 cannot release energy through either fission or fusion?
A Iron-56 lies at the peak of the binding energy curve, so splitting or combining it would decrease binding energy per nucleon and require energy input rather than releasing it
B Iron-56 has too few protons to undergo any nuclear reaction
C Uranium-235 is not radioactive, so only it can undergo fission
D Iron-56 nuclei are too small to be detected by neutron bombardment

Because iron-56 sits at the peak of the binding energy per nucleon curve, any reaction that splits it (fission) or combines it with another nucleus (fusion) would move it to a position of lower binding energy per nucleon, meaning the reaction would absorb rather than release energy. "Uranium-235 is not radioactive, so only it can undergo fission" is factually false, since uranium-235 is indeed a naturally radioactive isotope, though its fission is typically neutron-induced rather than spontaneous in reactors. This explains why iron marks the theoretical endpoint for exothermic nuclear reactions in stars and reactors alike.

Q58. A sample initially contains \(N_0\) atoms of a radioisotope with half-life \(t_{1/2}\). Which expression correctly gives the number of atoms remaining after time \(t\)?
A \(N = N_0\left(\frac{1}{2}\right)^{t/t_{1/2}}\)
B \(N = N_0\left(\frac{1}{2}\right)^{t_{1/2}/t}\)
C \(N = N_0 \cdot 2^{t/t_{1/2}}\)
D \(N = N_0 - \frac{t}{t_{1/2}}\)

The correct exponential decay formula raises \(\frac{1}{2}\) to the power of the number of half-lives elapsed, \(t/t_{1/2}\), ensuring the remaining amount halves exactly once every half-life period. The choice \(N = N_0 \cdot 2^{t/t_{1/2}}\) incorrectly causes the amount to grow rather than shrink over time, which contradicts the physical process of decay. This formula generalizes half-life calculations to any elapsed time, not just whole-number multiples of the half-life.

Q59. A deuterium-tritium fusion reaction releases about $17.6\,MeV$ per reaction, while a typical uranium-235 fission event releases about $200\,MeV$. Which statement correctly compares their energy release per unit mass of fuel?
A Fusion releases more energy per unit mass of fuel because deuterium and tritium are much lighter than uranium-235, so far more fusion reactions occur per gram
B Fission releases more energy per unit mass because $200\,MeV$ is greater than $17.6\,MeV$
C The two reactions release identical energy per unit mass
D Fusion releases less energy per unit mass because the reaction produces fewer particles

Although a single fission event releases far more energy than a single fusion event, deuterium and tritium have such small atomic masses compared to uranium-235 that many more fusion reactions occur in a given mass of fuel, resulting in a greater total energy release per gram for fusion. "Fission releases more energy per unit mass because $200\,MeV$ is greater than $17.6\,MeV$" mistakenly compares energy per single reaction rather than energy per unit mass of fuel, which requires accounting for the number of atoms per gram. Comparing nuclear fuels fairly always requires normalizing energy output to a common mass basis, not just comparing per-reaction energy values.

Q60. Which factor best explains why elements heavier than iron are typically produced by processes other than exothermic nuclear fusion, such as supernova nucleosynthesis?
A Fusing nuclei heavier than iron would decrease binding energy per nucleon, so the reaction absorbs energy instead of releasing it
B Elements heavier than iron cannot exist in nature
C Supernovae only produce hydrogen and helium
D Fusion reactions stop entirely once a star exceeds a certain temperature

Since iron-56 sits at the peak of the binding energy per nucleon curve, fusing nuclei beyond iron would move them further down the declining side of the curve, meaning the reaction would require a net input of energy rather than releasing it, so ordinary stellar fusion cannot proceed exothermically past this point. "Elements heavier than iron cannot exist in nature" is contradicted by the existence of common heavy elements like gold and uranium, which are known to form through non-fusion processes like rapid neutron capture during supernovae. This limitation explains why extreme, energy-absorbing astrophysical events like supernovae, rather than ordinary stellar fusion, are required to synthesize elements heavier than iron.

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Quick summary

This unit covers radioactive decay, half-life and fission and fusion — essential concepts for Chemistry. Use our interactive study games to test your understanding, or review questions in traditional format below.

Key concepts
  • Radioactive decay
  • Half-life
  • Fission and fusion
What you need to know

Key Concepts Breakdown

1 Radioactive Decay

Radioactive decay is the spontaneous breakdown of an unstable nucleus, releasing particles or energy. Students must know the three main types: alpha (α), beta (β), and gamma (γ) decay, including what is emitted and how the atomic number and mass number change. Balancing nuclear equations by conserving both mass number and atomic number is a core exam skill.

Key Points

  • Alpha decay: emits ²⁴He; mass number decreases by 4, atomic number decreases by 2
  • Beta decay: emits ⁰₋₁e; mass number stays the same, atomic number increases by 1
  • Gamma decay: emits high-energy photons (⁰₀γ); no change in mass number or atomic number
  • In any nuclear equation, the sum of mass numbers and the sum of atomic numbers must be equal on both sides
Example

Uranium-238 undergoes alpha decay. Write the nuclear equation and identify the daughter nucleus.

Explanation

Start with ²³⁸₉₂U and subtract a ⁴₂He (alpha particle): 238 − 4 = 234 for the new mass number, and 92 − 2 = 90 for the new atomic number. Atomic number 90 is Thorium, so the daughter nucleus is ²³⁴₉₀Th, giving the equation ²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He.

2 Half-Life

Half-life is the time required for exactly half of a radioactive sample to decay. Students must be able to calculate the remaining amount of a substance after a given number of half-lives using the formula: remaining amount = initial amount × (1/2)ⁿ, where n is the number of half-lives elapsed. Half-life is constant for a given isotope and is not affected by temperature, pressure, or chemical state.

Key Points

  • After each half-life, exactly half of the remaining radioactive nuclei have decayed
  • Formula: A = A₀ × (1/2)ⁿ, where n = total time ÷ half-life
  • After 1 half-life: 50% remains; after 2: 25%; after 3: 12.5%; after 4: 6.25%
  • Carbon-14 (t½ ≈ 5,730 years) is commonly used in exam contexts for radioactive dating problems
Example

A sample of Iodine-131 has a half-life of 8 days. If you start with 80 g, how much remains after 32 days?

Explanation

First, find the number of half-lives: 32 days ÷ 8 days = 4 half-lives. Then apply the formula: 80 × (1/2)⁴ = 80 × (1/16) = 5 g. After 32 days, 5 grams of Iodine-131 remain.

3 Fission and Fusion

Nuclear fission is the splitting of a large, heavy nucleus into two smaller nuclei, releasing a large amount of energy; nuclear fusion is the combining of two light nuclei into a heavier nucleus, also releasing energy. Students must know that both processes convert a small amount of mass into energy according to Einstein's equation E = mc². For the exam, know which process powers nuclear reactors (fission) and which powers the sun (fusion).

Key Points

  • Fission: a heavy nucleus (e.g., U-235) absorbs a neutron and splits, releasing energy and 2–3 more neutrons (chain reaction)
  • Fusion: light nuclei (e.g., hydrogen isotopes deuterium and tritium) combine to form helium, releasing more energy per gram than fission
  • Both processes release energy because the products have less mass than the reactants (mass defect); the lost mass becomes energy via E = mc²
  • Fission is used in nuclear power plants and atomic bombs; fusion powers stars and is the basis of hydrogen bombs
Example

In a fission reaction, U-235 absorbs a neutron and splits into Kr-92 and Ba-141. How many neutrons are released?

Explanation

Write the equation: ¹n + ²³⁵₉₂U → ⁹²₃₆Kr + ¹⁴¹₅₆Ba + x¹n. Check mass numbers: 1 + 235 = 236 on the left; 92 + 141 + x on the right. Solving: 236 = 233 + x, so x = 3 neutrons are released. Always verify atomic numbers balance as well: 0 + 92 = 36 + 56 = 92. ✓

FAQ

Questions, answered.

What is Nuclear Chemistry?

Nuclear Chemistry is Unit 9 of Chemistry, covering radioactive decay, half-life and fission and fusion.

How to study for Chemistry Unit 9?

Start with the Quick Summary above, review the Key Concepts, then test yourself with our interactive study games. Aim for 80%+ accuracy before moving on.

How many questions are in this unit?

This unit has 60 review questions, each with a written explanation, playable across 5 different game modes or readable in plain-text mode.