AP Biology Unit 3: Cellular Energetics — Free Review Games.
This unit covers photosynthesis, cell respiration and ATP cycle — essential concepts for AP Biology. Use our interactive study games to test your understanding, or review questions in traditional format below.
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Q1. In which organelle do the light-dependent reactions of photosynthesis occur?
Light-dependent reactions take place in the thylakoid membranes of chloroplasts, where photosystems capture light energy.
Q2. What is the net ATP yield from one molecule of glucose during glycolysis?
Glycolysis produces 4 ATP but consumes 2 ATP in the investment phase, yielding a net gain of 2 ATP per glucose.
Q3. What is the final electron acceptor in aerobic cellular respiration?
Oxygen accepts electrons at the end of the electron transport chain, combining with H+ to form water.
Q4. The Calvin cycle uses CO2, ATP, and NADPH to produce:
The Calvin cycle fixes CO2 into G3P, a three-carbon sugar that can be used to build glucose and other organic molecules.
Q5. Where does glycolysis occur in the cell?
Glycolysis occurs in the cytoplasm of both prokaryotic and eukaryotic cells and does not require an organelle.
Q6. During the Krebs cycle, acetyl-CoA is completely oxidized. What are the main products per turn of the cycle?
Each turn of the Krebs cycle produces 1 GTP (equivalent to ATP), 3 NADH, and 1 FADH2 from the oxidation of acetyl-CoA.
Q7. What role does the proton gradient across the inner mitochondrial membrane play in ATP synthesis?
The proton gradient (proton-motive force) drives H+ through ATP synthase, which uses this energy to phosphorylate ADP into ATP via chemiosmosis.
Q8. Which molecule directly provides the energy to do most cellular work?
ATP is the immediate energy currency of cells; hydrolysis of its terminal phosphate group releases energy for cellular processes.
Q9. In photosynthesis, water molecules are split during which process?
Water is split (photolysis) at Photosystem II during the light reactions, releasing electrons, H+, and O2.
Q10. During fermentation in animal cells, pyruvate is converted to:
In animal cells, anaerobic fermentation converts pyruvate to lactate, regenerating NAD+ so glycolysis can continue.
Q11. If a plant is given radioactively labeled H2O (H2^18O), in which product of photosynthesis will the ^18O label appear?
The oxygen released during photosynthesis comes from the splitting of water molecules, so the labeled oxygen from H2^18O appears in O2.
Q12. Cyanide blocks cytochrome c oxidase (Complex IV) of the electron transport chain. What is the immediate effect on the proton gradient?
Blocking Complex IV halts electron flow through the entire chain, stopping proton pumping and causing the gradient to dissipate as protons leak back.
Q13. A scientist measures the rate of photosynthesis at increasing light intensities while keeping CO2 and temperature constant. At high light intensity, the rate plateaus. Which factor is most likely limiting?
When light is saturating, the rate of the Calvin cycle becomes limited by CO2 fixation capacity (RuBisCO) or available CO2 concentration.
Q14. Why does the oxidation of FADH2 yield fewer ATP than the oxidation of NADH?
FADH2 enters the electron transport chain at Complex II rather than Complex I, so fewer protons are pumped across the membrane, yielding less ATP.
Q15. CAM plants open their stomata at night and fix CO2 into organic acids. What is the primary advantage of this adaptation?
By opening stomata at night when temperatures are lower, CAM plants minimize water loss through transpiration while still acquiring CO2 for daytime photosynthesis.
Q16. Which pigment is primarily responsible for capturing light energy during photosynthesis in plants?
Chlorophyll a is the primary photosynthetic pigment and is found in both photosystem I and photosystem II. It directly participates in the light reactions by absorbing red and blue-violet light and passing excited electrons to the reaction center. Carotenoids and xanthophylls are accessory pigments that absorb different wavelengths and transfer energy to chlorophyll a, but they do not directly drive the light reactions.
Q17. Which molecules are produced by the light-dependent reactions of photosynthesis and used directly as inputs for the Calvin cycle?
The light-dependent reactions convert light energy into chemical energy in the form of ATP and NADPH. These two molecules are then consumed in the Calvin cycle to power carbon fixation and the reduction of 3-PGA to G3P. Oxygen is a byproduct of the light reactions, not a Calvin cycle input. G3P and RuBP are products of and participants in the Calvin cycle itself.
Q18. How many turns of the Calvin cycle are required to produce one net molecule of G3P (glyceraldehyde-3-phosphate)?
Each turn of the Calvin cycle fixes one molecule of CO2 into a 3-carbon compound (3-PGA). Since G3P is a 3-carbon molecule, three turns are needed to incorporate enough carbon to yield one net G3P. The other five G3P molecules produced in three turns are used to regenerate three molecules of RuBP, keeping the cycle running.
Q19. What is the primary role of NAD+ during glycolysis?
NAD+ acts as an electron carrier. During glycolysis, the oxidation of glyceraldehyde-3-phosphate transfers electrons and hydrogen to NAD+, reducing it to NADH. This oxidation step is coupled to substrate-level phosphorylation, producing ATP. If NAD+ is not regenerated, glycolysis halts because there is no electron acceptor available, which is why fermentation regenerates NAD+ under anaerobic conditions.
Q20. In which compartment of the mitochondrion does the Krebs cycle take place?
The Krebs cycle occurs in the mitochondrial matrix, the aqueous interior enclosed by the inner membrane. The matrix contains all the soluble enzymes needed for the cycle, as well as the pyruvate dehydrogenase complex. The inner mitochondrial membrane is the site of the electron transport chain and ATP synthase, while the intermembrane space is where protons accumulate to form the gradient.
Q21. What does the electron transport chain produce that directly drives ATP synthesis by ATP synthase?
As electrons move through the ETC complexes, protons are actively pumped from the matrix into the intermembrane space, creating an electrochemical gradient (high [H+] outside, low inside). This proton-motive force drives H+ back into the matrix through ATP synthase, and that flow powers the rotation of the enzyme's F0 subunit, which catalyzes ATP synthesis. NADH donates electrons to the ETC but does not directly make ATP.
Q22. During fermentation, regenerating NAD+ from NADH is essential primarily because NAD+ is needed to:
Glycolysis requires NAD+ as an electron acceptor during the oxidation of glyceraldehyde-3-phosphate. Without a way to recycle NADH back to NAD+, glycolysis would stall and ATP production would stop. Fermentation (lactic acid or alcoholic) regenerates NAD+ in the cytoplasm without oxygen, allowing the cell to continue glycolysis and produce the 2 ATP per glucose it provides. The Krebs cycle does not occur during fermentation.
Q23. In the chloroplast, the proton gradient that drives ATP synthesis by CF1-CF0 ATP synthase is established by the light reactions. In which direction do protons flow through ATP synthase to produce ATP?
During the light reactions, water is split in the thylakoid lumen and protons are pumped from the stroma into the lumen by the plastoquinone shuttle and cytochrome b6f complex, creating a high [H+] inside the thylakoid. Protons then flow down their concentration gradient from the lumen back into the stroma through ATP synthase, powering ATP production. This is analogous to mitochondrial chemiosmosis but in the opposite membrane orientation.
Q24. When pyruvate is converted to acetyl-CoA by the pyruvate dehydrogenase complex, what happens to the carbon atom that is removed from pyruvate?
Pyruvate (3 carbons) undergoes oxidative decarboxylation: one carbon is removed as CO2, and the remaining 2-carbon acetyl group is attached to coenzyme A, forming acetyl-CoA. NADH is also produced as the electrons from this oxidation are transferred to NAD+. The CO2 is a waste product that diffuses out of the mitochondrion and eventually leaves the cell.
Q25. RuBisCO catalyzes the first step of the Calvin cycle. Which molecule does RuBisCO join CO2 to during carbon fixation?
RuBisCO (ribulose-1,5-bisphosphate carboxylase/oxygenase) catalyzes the carboxylation of RuBP, a 5-carbon molecule, by one CO2. The resulting unstable 6-carbon intermediate immediately splits into two molecules of 3-phosphoglycerate (3-PGA). G3P is produced later in the cycle after ATP and NADPH are used to reduce 3-PGA. ATP and NADPH are used in subsequent steps but are not the substrate for carbon fixation.
Q26. Substrate-level phosphorylation differs from oxidative phosphorylation in that substrate-level phosphorylation:
In substrate-level phosphorylation, an enzyme directly transfers a phosphate group from a phosphorylated substrate molecule (such as phosphoenolpyruvate or succinyl-CoA) to ADP, forming ATP without requiring a proton gradient or the ETC. This occurs in both glycolysis and the Krebs cycle. Oxidative phosphorylation, in contrast, uses the proton-motive force established by the ETC to drive ATP synthase and accounts for the majority of ATP produced per glucose.
Q27. Why is oxygen essential as the final electron acceptor in aerobic cellular respiration?
The ETC is essentially a series of redox reactions. Electrons must have a final acceptor at the end of the chain. Oxygen accepts electrons from Complex IV and combines with protons to form water. If oxygen is absent, the ETC stalls because electrons have nowhere to go; NADH and FADH2 cannot be oxidized, NAD+ and FAD are not regenerated, and the Krebs cycle and glycolysis halt. Oxygen itself does not make ATP directly — that is the job of ATP synthase.
Q28. In non-cyclic photophosphorylation, electrons released from photosystem II ultimately end up reducing which molecule at the end of the electron flow pathway?
In the non-cyclic pathway, electrons flow from water (split at PSII) through plastoquinone, the cytochrome b6f complex, plastocyanin, and photosystem I, and are finally transferred via ferredoxin to NADP+ reductase, which reduces NADP+ to NADPH. NADP+ is the ultimate electron acceptor of the light reactions. ADP is phosphorylated to ATP separately using the proton gradient, and the cytochrome b6f complex is an intermediate, not the final acceptor.
Q29. Which statement best describes how ATP functions as an energy currency molecule in the cell?
ATP contains two phosphoanhydride bonds connecting its three phosphate groups. Hydrolysis of the terminal phosphate bond releases approximately 7.3 kcal/mol of free energy under standard conditions (more under cellular conditions). This energy is coupled to endergonic reactions, powering cellular work. The energy does not come from carbon-nitrogen bonds. ATP is synthesized using energy from the proton gradient (oxidative phosphorylation) or substrate-level phosphorylation, not by directly accepting electrons from NADH.
Q30. How many total molecules of ATP and NADPH are consumed by the Calvin cycle to fix 3 molecules of CO2 and produce one net molecule of G3P?
Three turns of the Calvin cycle fix 3 CO2, producing six 3-PGA molecules. The reduction phase uses 6 ATP and 6 NADPH to convert six 3-PGA to six G3P. Five of those G3P are used to regenerate three RuBP molecules, consuming an additional 3 ATP. Total: 9 ATP and 6 NADPH per net G3P. This 3:2 ratio of ATP to NADPH matches what the light reactions produce under normal conditions.
Q31. Cyclic photophosphorylation involves only photosystem I and produces ATP but not NADPH or O2. Under what condition would cyclic photophosphorylation be most advantageous?
The Calvin cycle requires ATP and NADPH in a ratio of approximately 3:2. Non-cyclic photophosphorylation produces these in roughly equal amounts. When NADPH accumulates faster than it is consumed (e.g., if CO2 is limiting), cyclic flow around PSI can produce additional ATP without generating more NADPH, correcting the imbalance. This is a regulatory mechanism that helps the cell fine-tune the output of the light reactions to match the demands of carbon fixation.
Q32. During the conversion of pyruvate to acetyl-CoA by the pyruvate dehydrogenase complex, which of the following is NOT produced?
The pyruvate dehydrogenase reaction produces three things: CO2 (from decarboxylation), NADH (from the oxidation of pyruvate), and acetyl-CoA (the 2-carbon acetyl group attached to coenzyme A). FADH2 is not produced in this step. FADH2 is generated later in the Krebs cycle when succinate is oxidized to fumarate by succinate dehydrogenase (Complex II). Confusing these two reactions is a common error.
Q33. Coenzyme Q (ubiquinone) shuttles electrons from Complexes I and II to Complex III in the electron transport chain. Which property of coenzyme Q makes it particularly well suited for this role?
Coenzyme Q is a small, hydrophobic (lipid-soluble) quinone molecule that dissolves in the lipid bilayer of the inner mitochondrial membrane. This allows it to diffuse freely within the membrane, collecting electrons from both Complex I (NADH-linked) and Complex II (FADH2-linked) and delivering them to Complex III. Unlike protein complexes that are embedded in fixed positions, CoQ's mobility makes it an ideal mobile electron carrier. It does not synthesize ATP.
Q34. Dinitrophenol (DNP) is a chemical uncoupler that carries protons across the inner mitochondrial membrane, bypassing ATP synthase. Which outcome would be expected in cells treated with DNP?
DNP collapses the proton gradient by allowing protons to leak back into the matrix without passing through ATP synthase. As the gradient dissipates, the ETC accelerates to try to restore it, consuming more NADH, FADH2, O2, and glucose. However, since protons bypass ATP synthase, little ATP is made. The energy of the gradient is released as heat instead. This is why DNP was once used as a dangerous weight-loss drug. NADH cannot accumulate indefinitely because the ETC, now running faster, oxidizes it more rapidly.
Q35. C3 plants undergo photorespiration when RuBisCO's oxygenase activity is favored over its carboxylase activity. Which statement best explains why photorespiration reduces the overall efficiency of photosynthesis?
When RuBisCO binds O2 instead of CO2, the RuBP is split into one 3-PGA and one 2-phosphoglycolate (2 carbons). The 2-phosphoglycolate cannot enter the Calvin cycle directly; it is processed in peroxisomes and mitochondria through photorespiratory reactions that consume ATP, release CO2, and regenerate only some 3-PGA. This wastes fixed carbon and energy without producing net sugar. C4 and CAM plants have evolved mechanisms to concentrate CO2 around RuBisCO to minimize this problem.
Q36. A researcher exposes a plant to 13C-labeled CO2 for a very brief pulse and then analyzes intermediates. Which Calvin cycle molecule would show radioactive 13C labeling first?
The first product of carbon fixation is 3-phosphoglycerate (3-PGA). When RuBisCO adds one CO2 to RuBP (5 carbons), the unstable 6-carbon intermediate immediately splits into two molecules of 3-PGA (3 carbons each), and the labeled carbon from CO2 appears in these 3-PGA molecules. G3P is produced later when 3-PGA is reduced using ATP and NADPH. RuBP is the substrate that accepts CO2, not a product. This experiment (Melvin Calvin's chromatography work) established the sequence of the cycle.
Q37. Suppose a mutation eliminates the proton-pumping activity of Complex I but leaves its ability to transfer electrons from NADH to coenzyme Q intact. What is the most accurate prediction of the effect on cellular respiration?
Complex I normally pumps 4 protons per electron pair, contributing significantly to the proton-motive force. If it can still pass electrons to CoQ but cannot pump protons, the ETC continues — electrons still flow to Complexes III and IV, which do pump protons, so ATP is still made. However, because fewer protons are pumped overall, the gradient is smaller and ATP yield per glucose falls substantially. FADH2 enters at Complex II, which does not pump protons at all regardless of mutation, so it cannot compensate.
Q38. Which experimental result provides the strongest direct evidence for the chemiosmotic theory of ATP synthesis?
The chemiosmotic theory proposes that the proton gradient itself — not any specific chemical intermediate — is the energy source for ATP synthesis. The most direct evidence is that reconstituted membrane vesicles containing only ATP synthase can produce ATP when an artificial pH gradient is imposed across them, with no ETC, no metabolic substrates, and no other proteins. This shows that the proton gradient alone is sufficient to drive ATP synthase. Detergent experiments show that membrane integrity matters but don't isolate the proton gradient as the specific driver.
Q39. The theoretical maximum ATP yield per glucose is about 30-32 ATP, yet cells typically produce fewer. Which combination of factors best accounts for this discrepancy between theoretical and actual yield?
Two major sources of inefficiency reduce actual ATP yield. First, the inner membrane is not perfectly impermeable to protons — some protons leak back into the matrix without passing through ATP synthase, dissipating part of the gradient as heat. Second, the proton-motive force powers not just ATP synthase but also membrane transport proteins such as the pyruvate carrier and the phosphate transporter, consuming protons for purposes other than ATP synthesis. The Krebs cycle does fully oxidize acetyl-CoA and FADH2 is fully oxidized; these are not the limiting factors under normal conditions.
Q40. A plant is illuminated exclusively with green light. Which prediction about photosynthetic rate is most accurate, and what is the best mechanistic explanation?
Chlorophyll a and b absorb light most efficiently in the red (around 680-700 nm) and blue-violet (around 430-450 nm) regions of the spectrum. Green light (around 500-560 nm) falls in the region where chlorophyll absorption is minimal — most green light is reflected, which is why leaves appear green. With only green light available, excitation of the reaction centers is greatly reduced and photosynthesis slows substantially. However, it would not stop entirely because carotenoid accessory pigments do absorb some green wavelengths, just very inefficiently.
Q41. Which photosynthetic pigment is primarily responsible for directly absorbing light energy and passing excited electrons into the photosystems?
Chlorophyll a is the primary reaction-center pigment in both Photosystem I and Photosystem II; it directly participates in the conversion of light energy to chemical energy. Chlorophyll b and carotenoids are accessory pigments that absorb light and transfer energy to chlorophyll a but do not themselves drive electron transfer.
Q42. In which region of the chloroplast does the Calvin cycle take place?
The Calvin cycle occurs in the stroma, the fluid-filled space surrounding the thylakoids. The enzymes of the Calvin cycle, including RuBisCO, are dissolved in the stroma. The thylakoid membrane and lumen are the sites of the light-dependent reactions, not carbon fixation.
Q43. Pyruvate, the end product of glycolysis, contains how many carbon atoms?
Pyruvate (pyruvic acid) is a 3-carbon molecule. Glucose (6 carbons) is split into two 3-carbon pyruvate molecules during glycolysis. The 2-carbon molecule acetyl-CoA is formed later when pyruvate loses one carbon as CO2 during pyruvate oxidation.
Q44. Which gas is released as a direct byproduct of the light-dependent reactions of photosynthesis?
Oxygen is released when water molecules are split during the light-dependent reactions in a process called photolysis. The electrons from water replace those lost by P680 in Photosystem II. Carbon dioxide is consumed (not released) during the Calvin cycle.
Q45. In which location within the mitochondrion does the Krebs cycle take place?
The Krebs cycle (citric acid cycle) takes place in the mitochondrial matrix, the innermost compartment of the mitochondrion. The enzymes that catalyze the cycle are dissolved in or embedded in the matrix. The inner mitochondrial membrane is the site of the electron transport chain and oxidative phosphorylation.
Q46. What is the primary role of NADH and FADH2 in cellular respiration?
NADH and FADH2 are electron carriers. They transfer high-energy electrons to the electron transport chain, where those electrons pass through protein complexes, releasing energy used to pump protons and ultimately drive ATP synthesis. They do not directly produce ATP; that is done by substrate-level phosphorylation or ATP synthase.
Q47. Which statement correctly describes the function of ATP synthase during cellular respiration?
ATP synthase (Complex V) harnesses the energy stored in the electrochemical proton gradient across the inner mitochondrial membrane. As protons flow back into the matrix through ATP synthase, the released energy drives the phosphorylation of ADP to ATP. The electron transport chain pumps protons, but ATP synthase does not itself transfer electrons.
Q48. Which molecules produced by the light-dependent reactions are directly consumed by the Calvin cycle?
The Calvin cycle requires ATP (for energy) and NADPH (as a reducing agent) to fix CO2 into G3P. Both are produced by the light-dependent reactions. After donating their energy and electrons, ATP becomes ADP and NADPH becomes NADP+, which are recycled back to the light reactions.
Q49. A plant is abruptly moved from bright sunlight into complete darkness. What is the most immediate effect on Calvin cycle activity?
The Calvin cycle depends on ATP and NADPH from the light-dependent reactions. When light is removed, production of ATP and NADPH stops immediately. Without these inputs, the reduction of 3-PGA to G3P stalls. RuBisCO itself is not directly light-regulated in the short term, and CO2 levels alone cannot sustain the cycle without the energy carriers.
Q50. One glucose molecule is completely oxidized through glycolysis and pyruvate oxidation before entering the Krebs cycle. How many acetyl-CoA molecules are delivered to the Krebs cycle per glucose molecule?
Glycolysis splits one 6-carbon glucose into two 3-carbon pyruvate molecules. Each pyruvate is then oxidized to one 2-carbon acetyl-CoA plus one CO2. Therefore, two acetyl-CoA molecules enter the Krebs cycle per glucose. Because the Krebs cycle turns once per acetyl-CoA, it completes two full turns per glucose.
Q51. Fermentation allows glycolysis to continue under anaerobic conditions. What is the primary biochemical reason fermentation is necessary for this continuation?
Glycolysis requires NAD+ as an electron acceptor to oxidize glucose. Under aerobic conditions, the ETC regenerates NAD+ from NADH. Anaerobically, fermentation regenerates NAD+ by transferring electrons from NADH to pyruvate (producing lactate or ethanol). Without this regeneration, NAD+ would be depleted and glycolysis would halt. Fermentation itself produces no new ATP.
Q52. In one complete turn of the Krebs cycle, how many carbon atoms are released as CO2 from a single acetyl-CoA molecule?
Acetyl-CoA (2 carbons) combines with oxaloacetate (4 carbons) to form citrate (6 carbons). During one turn of the Krebs cycle, two decarboxylation reactions occur (at isocitrate dehydrogenase and alpha-ketoglutarate dehydrogenase), each releasing one CO2. This accounts for both carbons originally from acetyl-CoA being released as 2 CO2.
Q53. A researcher adds an uncoupling agent that makes the inner mitochondrial membrane freely permeable to protons. Which outcome would be expected?
Uncouplers (like DNP) dissipate the proton gradient by allowing protons to cross the membrane without passing through ATP synthase. The energy of the gradient is released as heat rather than used to make ATP. The ETC continues to pump protons and consume NADH and FADH2, but because the gradient is not maintained, ATP synthesis drops dramatically. This principle is related to how brown fat generates body heat.
Q54. Why are the cristae (inner folds) of the inner mitochondrial membrane important for cellular respiration?
The cristae dramatically increase the surface area of the inner mitochondrial membrane. Because the electron transport chain complexes and ATP synthase are embedded in this membrane, greater surface area means more capacity for these proteins, and therefore greater ATP production. A mitochondrion with more cristae can produce more ATP — consistent with the observation that highly active cells (like cardiac muscle) have mitochondria with densely packed cristae.
Q55. In the light-dependent reactions, electrons lost from the P680 reaction center of Photosystem II are replaced by electrons from which source?
P680 is the strongest biological oxidizing agent known. After it ejects an excited electron, it has a strong tendency to pull electrons from water. The oxygen-evolving complex splits water molecules in the thylakoid lumen, releasing O2, H+ ions, and electrons that replenish P680. This is why oxygenic photosynthesis produces O2 as a byproduct.
Q56. Which statement best distinguishes substrate-level phosphorylation from oxidative phosphorylation?
In substrate-level phosphorylation (occurring in glycolysis and the Krebs cycle), a phosphate group is transferred directly from a phosphorylated intermediate to ADP, forming ATP. No proton gradient is required. Oxidative phosphorylation uses the proton-motive force generated by the ETC to drive ATP synthase. Substrate-level phosphorylation accounts for only 4 ATP per glucose, while oxidative phosphorylation accounts for approximately 26-28 ATP.
Q57. If the concentration of ADP in a cell increases sharply due to high energy demand, what effect would this most likely have on the rate of cellular respiration?
ADP is an allosteric activator of phosphofructokinase-1 (PFK-1), the main regulatory enzyme of glycolysis, as well as other enzymes in the respiratory pathway. High ADP signals that the cell needs more ATP, stimulating the entire respiration process. Conversely, high ATP inhibits PFK-1, slowing respiration when energy is plentiful. This feedback regulation matches ATP production to cellular demand.
Q58. In both chloroplasts and mitochondria, ATP is made by chemiosmosis. Which statement correctly describes the location of proton accumulation and the direction of proton flow through ATP synthase in each organelle?
Despite both using chemiosmosis, the topology differs. In chloroplasts, the ETC pumps protons from the stroma into the thylakoid lumen, building a high proton concentration there; ATP synthase then allows protons to flow back into the stroma, synthesizing ATP on the stromal side. In mitochondria, the ETC pumps protons from the matrix into the intermembrane space; ATP synthase allows them to flow back into the matrix. In both cases, protons flow from a region of higher concentration to lower concentration through ATP synthase.
Q59. A mutation renders phosphofructokinase-1 (PFK-1) insensitive to inhibition by high ATP concentrations. What is the most likely consequence for a cell expressing only this mutant enzyme?
PFK-1 is the primary committed step of glycolysis and is normally inhibited by high ATP (signaling sufficient energy). Without this feedback inhibition, glycolysis would continue at maximum rate regardless of the cell's energy status. This would continuously produce pyruvate, potentially overwhelming the Krebs cycle and ETC, deplete glucose stores unnecessarily, and disrupt normal metabolic regulation. This concept is related to the Warburg effect observed in cancer cells.
Q60. C4 plants use a two-stage carbon fixation strategy involving mesophyll and bundle sheath cells. What is the primary adaptive advantage of this mechanism in hot, dry environments?
In hot, dry conditions, plants partially close stomata to reduce water loss. This decreases internal CO2 and increases O2, promoting photorespiration in C3 plants (RuBisCO fixing O2 instead of CO2). C4 plants combat this by first fixing CO2 into 4-carbon acids in mesophyll cells using PEP carboxylase (which has higher CO2 affinity than RuBisCO), then releasing concentrated CO2 around RuBisCO in bundle sheath cells. This suppresses photorespiration at a cost of extra ATP.
Q61. A mutation completely eliminates the function of Complex I (NADH dehydrogenase). How would this specifically affect NADH and FADH2 utilization in oxidative phosphorylation?
NADH donates electrons specifically to Complex I, which feeds them into the ubiquinone pool. FADH2 donates electrons to Complex II (succinate dehydrogenase), which is an entirely separate entry point into the ubiquinone pool and does not depend on Complex I. Therefore, eliminating Complex I blocks NADH oxidation but leaves the FADH2 pathway intact. This also explains why FADH2 yields fewer ATP than NADH — it enters downstream in the chain, bypassing the proton-pumping step at Complex I.
Q62. Oligomycin blocks the proton channel (Fo subunit) of ATP synthase, preventing proton flow through it. Assuming the electron transport chain continues pumping protons initially, what happens to the mitochondrial proton gradient?
When ATP synthase is blocked, protons pumped by the ETC cannot return to the matrix and accumulate in the intermembrane space. The proton gradient (both the concentration gradient and the membrane potential) increases. This backpressure eventually makes it energetically unfavorable for the ETC to continue pumping protons, slowing and ultimately halting electron transport. This demonstrates that ATP synthesis and electron transport are tightly coupled — they cannot continue independently.
Q63. Photorespiration in C3 plants occurs when RuBisCO oxygenates RuBP instead of carboxylating it. Under which conditions is photorespiration most likely to increase, and what is its net effect on plant productivity?
On hot, dry days, plants close stomata to conserve water. This traps O2 (from photosynthesis) inside the leaf while CO2 is consumed, raising the O2:CO2 ratio. RuBisCO has low discrimination between CO2 and O2; with more O2 available, it increasingly oxygenates RuBP. The products enter a costly recovery pathway (photorespiratory pathway) that consumes ATP and NADPH and releases CO2 without producing sugar, potentially reducing net carbon gain by 25-50% in C3 plants under hot conditions.
Q64. The theoretical ATP yield per glucose has been revised downward from the classic 36-38 ATP to approximately 30-32 ATP. Which factor best explains this revision?
The classical estimate assumed exactly 3 ATP per NADH and 2 per FADH2, based on a simple 3 H+/ATP ratio. Biochemical measurements show ATP synthase requires approximately 8-10 H+ per full rotation to synthesize 3 ATP (roughly 2.7 H+ per ATP). Additionally, transporting ATP out and ADP and Pi in via the ATP/ADP translocase costs approximately 1 H+ per ATP, and importing pyruvate costs energy. These real stoichiometric costs reduce the overall yield to approximately 30-32 ATP.
Q65. In cyclic photophosphorylation, electrons from Photosystem I cycle back through the electron transport chain rather than reducing NADP+. What does this pathway produce, and under what metabolic condition might it be favored?
Cyclic photophosphorylation involves electrons from P700 (PSI) being passed to ferredoxin and then back through the plastoquinone pool and the cytochrome b6f complex, pumping protons and generating a proton gradient that drives ATP synthesis. No NADPH is made and no water is split. The Calvin cycle consumes ATP and NADPH in an approximately 3:2 ratio. If NADPH is produced faster than it is consumed, cycling allows extra ATP to be generated without producing additional NADPH, balancing the ratio to meet Calvin cycle demands.
Q66. Which of the following molecules serves as the primary electron carrier in the light-dependent reactions of photosynthesis?
NADPH is the primary electron carrier produced during the light-dependent reactions. It carries high-energy electrons to the Calvin cycle where they are used to reduce CO2 into G3P. FADH2 is produced in the mitochondria during the Krebs cycle, not in chloroplasts.
Q67. During aerobic cellular respiration, where does the Krebs cycle take place?
The Krebs cycle occurs in the mitochondrial matrix, the fluid-filled interior of the mitochondrion. The electron transport chain is located on the inner mitochondrial membrane, while glycolysis occurs in the cytoplasm.
Q68. What is the three-carbon product of the Calvin cycle that can be used to build glucose?
G3P (glyceraldehyde-3-phosphate) is the three-carbon sugar produced by the Calvin cycle. It is the direct output that can be used to synthesize glucose and other organic molecules. Pyruvate is a product of glycolysis, not the Calvin cycle.
Q69. Which of the following correctly describes the role of oxygen in aerobic respiration?
Oxygen serves as the final electron acceptor in the electron transport chain, combining with electrons and protons to form water. Without oxygen, the ETC would halt because electrons would have nowhere to go. Oxygen does not participate in glycolysis.
Q70. Which pigment absorbs light energy and transfers it to the reaction center in a photosystem?
Antenna pigments — including chlorophyll b and carotenoids — absorb light and funnel energy to the reaction center. Chlorophyll a is found both as an antenna pigment and at the reaction center; only the special pair of chlorophyll a at the reaction center undergoes actual charge separation. The key concept is that multiple pigment types collectively harvest light.
Q71. What is produced when pyruvate is converted to acetyl-CoA before entering the Krebs cycle?
Pyruvate decarboxylation produces CO2 (lost as a carbon), NADH (from NAD+ reduction), and acetyl-CoA. This step, called pyruvate oxidation, occurs in the mitochondrial matrix and links glycolysis to the Krebs cycle. FADH2 is not produced in this step.
Q72. In the light-dependent reactions, what provides the electrons that replace those lost by chlorophyll at Photosystem II?
Water is split (photolysis) at Photosystem II to provide replacement electrons. This oxidation of water also releases O2 as a byproduct and protons that contribute to the proton gradient. CO2 is not involved in the light reactions; it is fixed in the Calvin cycle.
Q73. A cell is treated with a drug that inhibits ATP synthase. Which of the following would be the most direct consequence?
ATP synthase uses the flow of protons down their gradient to synthesize ATP. If it is inhibited, protons pumped by the ETC cannot flow back into the matrix, causing the proton gradient to become steeper and steeper. The ETC itself would eventually slow as the gradient becomes too large to pump against, but the immediate direct consequence is gradient buildup, not collapse.
Q74. C4 plants reduce photorespiration by pre-fixing CO2 into a four-carbon compound in mesophyll cells before passing it to bundle sheath cells. What is the primary advantage of this adaptation?
RuBisCO can bind O2 instead of CO2, leading to photorespiration, which wastes energy. C4 plants concentrate CO2 in bundle sheath cells, saturating RuBisCO with CO2 and suppressing its oxygenase activity. This increases the efficiency of carbon fixation. The Calvin cycle still requires ATP and NADPH in C4 plants.
Q75. During anaerobic fermentation in yeast, pyruvate is converted to ethanol. What is the metabolic purpose of this conversion?
Fermentation does not produce additional ATP. Its sole metabolic purpose is to oxidize NADH back to NAD+, which is required for glycolysis to continue. Without NAD+, glycolysis would halt and the cell would receive no ATP at all. Ethanol is simply the byproduct that accepts the electrons.
Q76. A researcher adds an uncoupler — a molecule that makes the inner mitochondrial membrane permeable to protons — to a cell. What would happen to oxygen consumption and ATP production?
Uncouplers dissipate the proton gradient by allowing protons to leak across the membrane without passing through ATP synthase, releasing energy as heat. With the gradient gone, the ETC can run faster (consuming more O2), but ATP synthase has no driving force, so ATP production drops. This is the mechanism behind some thermogenic tissues.
Q77. In the Z-scheme of photosynthesis, electrons move from Photosystem II to Photosystem I through the electron transport chain. What is the primary function of this electron flow?
As electrons pass through the plastoquinone, cytochrome b6f complex, and plastocyanin, protons are pumped into the thylakoid lumen. This builds a proton gradient that drives ATP synthase (chemiosmosis) to produce ATP. NADPH is produced later when electrons from PSI reduce NADP+, and water splitting occurs at PSII independently.
Q78. Which of the following best explains why cellular respiration is considered an exergonic process?
Exergonic reactions release free energy because products have lower free energy than reactants. Glucose and O2 are high-energy molecules; CO2 and H2O are low-energy products. The released energy is captured as ATP. Cellular respiration does not require light, and while heat is produced, that is a consequence of the process, not the definition of exergonic.
Q79. Rubisco catalyzes the first step of the Calvin cycle. Which molecules are the substrates for this reaction?
RuBisCO (ribulose-1,5-bisphosphate carboxylase/oxygenase) catalyzes the carboxylation of RuBP (ribulose-1,5-bisphosphate) with CO2 to form an unstable six-carbon intermediate that immediately splits into two molecules of 3-phosphoglycerate (3-PGA). G3P is a later product, not a substrate.
Q80. During the Krebs cycle, how many times does substrate-level phosphorylation occur per acetyl-CoA that enters the cycle?
Per turn of the Krebs cycle (one acetyl-CoA), substrate-level phosphorylation occurs once, producing one GTP (equivalent to one ATP) when succinyl-CoA is converted to succinate by succinyl-CoA synthetase. The majority of energy is captured as NADH and FADH2, not through substrate-level phosphorylation.
Q81. A plant leaf is placed in a sealed chamber in the dark. Over time, the concentration of CO2 in the chamber increases. What process primarily accounts for this CO2 increase?
In the dark, photosynthesis cannot occur. The plant continues performing cellular respiration, oxidizing glucose to produce ATP, and releasing CO2 as a byproduct. Photorespiration requires light and RuBisCO activity. Fermentation in plants is limited and would require anaerobic conditions.
Q82. What happens to the carbon atoms from acetyl-CoA after one complete turn of the Krebs cycle?
The two carbons entering as acetyl-CoA are released as two molecules of CO2 during one turn of the Krebs cycle (once when isocitrate is oxidized and once when alpha-ketoglutarate is oxidized). The carbon skeleton is not stored in NADH or ATP; the electrons and protons are carried by NADH and FADH2, but not the carbon atoms.
Q83. A mutation eliminates the ability of the cytochrome b6f complex in chloroplasts to pump protons. Which of the following would be the most likely consequence for the cell?
The cytochrome b6f complex is responsible for pumping protons into the thylakoid lumen during the light reactions, creating the proton gradient that drives ATP synthase (photophosphorylation). Without proton pumping, the gradient collapses, and ATP synthesis halts. Water splitting is an independent process at PSII and would not be directly blocked.
Q84. An experiment measures ATP production in isolated mitochondria under two conditions: (1) glucose provided, (2) only pyruvate and oxygen provided. Condition 2 produces more ATP per carbon than Condition 1. Which of the following best explains this result?
Glycolysis occurs in the cytoplasm, not in mitochondria. In Condition 1, isolated mitochondria cannot break down glucose because they lack cytoplasmic glycolytic enzymes, so glucose is unavailable to them. In Condition 2, pyruvate enters directly and is fully oxidized via pyruvate decarboxylation, the Krebs cycle, and oxidative phosphorylation — yielding the maximum ATP per carbon. The discrepancy reflects this compartmentalization.
Q85. A plant is grown under conditions where only red light is available. Compared to a plant grown under white light, which of the following outcomes would you predict?
Chlorophyll a and b absorb red light (around 680-700 nm) most effectively, so red-only light can drive photosynthesis. However, white light also includes blue wavelengths absorbed by carotenoids, which funnel energy to chlorophyll, boosting total light harvesting. Under red-only light, photosynthesis occurs but is slightly less efficient than under white light due to reduced carotenoid contribution — making choice A the best of the options since it correctly identifies that red light IS efficiently absorbed. Choice B is partially correct in concept but overstates the limitation.
Q86. In a cell where the NAD+/NADH ratio drops very low (most NAD+ is reduced to NADH), what would most likely happen to glycolysis?
Glycolysis requires NAD+ as an electron acceptor at the glyceraldehyde-3-phosphate dehydrogenase (GAPDH) step, where G3P is oxidized to 1,3-bisphosphoglycerate. If NAD+ is depleted, this step cannot proceed, and glycolysis halts. This is why fermentation (regenerating NAD+ from NADH) is critical for glycolysis to continue under anaerobic conditions. GAPDH uses only NAD+, not FAD.
Q87. Chemiosmosis in chloroplasts involves protons moving from the thylakoid lumen into the stroma through ATP synthase. Which of the following correctly describes the direction and reason for this proton flow?
During the light reactions, protons accumulate in the thylakoid lumen (from water splitting and proton pumping by cytochrome b6f), creating a steep proton gradient. Protons then flow down this concentration gradient from the lumen (high [H+]) into the stroma (low [H+]) through ATP synthase. This downhill movement releases free energy that is used to phosphorylate ADP to ATP — this is chemiosmosis.
Q88. A researcher blocks the regeneration of RuBP in the Calvin cycle. Which of the following would be the immediate effect on the light-dependent reactions?
The Calvin cycle consumes ATP and NADPH produced by the light reactions. If RuBP regeneration is blocked, the Calvin cycle slows and stops consuming ATP and NADPH. As these molecules accumulate, the supply of ADP and NADP+ — the substrates needed for the light reactions to function — is depleted. This feedback causes the light reactions to slow down. RuBP regeneration has no direct role in the proton gradient.
Q89. Why does aerobic respiration yield dramatically more ATP than anaerobic fermentation from the same glucose molecule?
Both processes begin with glycolysis, yielding 2 net ATP. In fermentation, NADH is simply oxidized back to NAD+ (via reduction of pyruvate to lactate or ethanol) with no additional ATP generated. In aerobic respiration, NADH and FADH2 carry electrons to the electron transport chain, generating a large proton gradient that drives ATP synthase to produce approximately 30-32 ATP via oxidative phosphorylation. The difference lies entirely in what happens to the electron carriers.
Q90. The light compensation point is where photosynthesis and respiration rates are equal. If a plant is kept just below its light compensation point for an extended period, what would happen?
Below the light compensation point, respiration consumes more glucose than photosynthesis produces. The plant must catabolize stored organic molecules (starch, then lipids) to meet its energy needs. Over time, it depletes these reserves and loses mass. Respiration rate is not simply adjustable to match photosynthesis — it reflects the cell's metabolic demand, and C4 switching is not an option for C3 plants.
Q91. Which bond in an ATP molecule releases the most usable energy when hydrolyzed during cellular work?
Hydrolysis of the terminal (gamma) phosphate bond releases approximately 7.3 kcal/mol of free energy under standard conditions, converting ATP to ADP and inorganic phosphate. This bond is considered high-energy because the products — ADP and Pi — are stabilized by resonance and relief of electrostatic repulsion, making the reaction thermodynamically favorable. The adenine-ribose bond is a glycosidic bond not involved in energy transfer, and the other phosphate bonds require separate enzymatic reactions to cleave.
Q92. Which molecules produced by the light reactions of photosynthesis are directly consumed to power the Calvin cycle?
The light reactions convert light energy into chemical energy stored in ATP and NADPH. These molecules are the direct inputs to the Calvin cycle: ATP provides phosphate groups and energy to drive reactions, while NADPH donates electrons to reduce 3-phosphoglycerate to G3P. Glucose is the final downstream product of the Calvin cycle, not a reactant. ADP and NADP+ are substrates consumed during the light reactions, not the energy-rich products delivered to the Calvin cycle.
Q93. In eukaryotic cells, glycolysis takes place in which cellular location?
Glycolysis occurs in the cytosol and does not require mitochondria or oxygen. All ten enzymatic steps from glucose to pyruvate take place in the soluble cytoplasm. This is why even prokaryotes and obligate anaerobes, which lack mitochondria, can perform glycolysis. The mitochondrial matrix houses the Krebs cycle enzymes, while the inner mitochondrial membrane is the site of the electron transport chain and ATP synthase.
Q94. Which molecule serves as the primary electron donor at Photosystem II during the light-dependent reactions of photosynthesis in plants?
Water is oxidized (split) at Photosystem II by the oxygen-evolving complex in a reaction called photolysis. This releases electrons that replace those ejected from the P680 reaction center chlorophyll when it absorbs light. The oxygen gas released by plants is entirely derived from water, not from CO2. NADPH is a product generated later in the light reactions at Photosystem I, not a donor to PSII. CO2 is fixed during the Calvin cycle and plays no role in the light reactions.
Q95. What is the primary role of NADPH in the Calvin cycle?
In the reduction phase of the Calvin cycle, each 3-PGA molecule is first phosphorylated by ATP, then reduced by NADPH — which donates its electrons — to produce G3P. NADPH acts as the electron donor (reducing agent) in this conversion. ATP, not NADPH, provides the phosphate groups needed for RuBP regeneration. Rubisco binds CO2 directly without a carrier molecule. NADPH is produced in the light reactions; it is not involved in light capture itself.
Q96. In which compartment of the mitochondria do the enzymatic reactions of the Krebs cycle (citric acid cycle) occur?
The soluble enzymes of the Krebs cycle are located in the mitochondrial matrix, the fluid-filled compartment enclosed by the inner membrane. Pyruvate is transported into the matrix, converted to acetyl-CoA by the pyruvate dehydrogenase complex, and then fully oxidized through the eight-step cycle. The inner mitochondrial membrane houses the electron transport chain complexes and ATP synthase. The intermembrane space is where protons accumulate to generate the electrochemical gradient used for ATP synthesis.
Q97. Which of the following best describes substrate-level phosphorylation?
Substrate-level phosphorylation occurs when a phosphate group is transferred directly from a phosphorylated organic substrate to ADP, producing ATP without involving a membrane or proton gradient. Classic examples include the conversion of 1,3-bisphosphoglycerate to 3-PGA in glycolysis and succinyl-CoA to succinate in the Krebs cycle. Choice B describes oxidative phosphorylation (chemiosmosis). The phosphorylation of glucose early in glycolysis actually consumes ATP rather than producing it, so it is not substrate-level phosphorylation.
Q98. What is the role of molecular oxygen (O2) at the end of the electron transport chain in aerobic cellular respiration?
At Complex IV (cytochrome c oxidase), electrons are passed from cytochrome c to molecular oxygen, which is reduced by accepting electrons and combining with protons to form water. Oxygen is essential because without a final electron acceptor, the electron transport chain would back up, halting NADH and FADH2 oxidation and stopping ATP production. Glucose oxidation proceeds through many enzyme-catalyzed steps, not direct reaction with O2. Proton pumping is carried out by Complexes I, III, and IV — oxygen does not perform this function directly.
Q99. A plant is moved into a chamber where CO2 concentration is doubled compared to normal atmosphere. Assuming light is abundant and not limiting, which of the following changes would most likely occur in the Calvin cycle in the short term?
Rubisco uses CO2 as a substrate; at elevated CO2, Rubisco is more frequently saturated, increasing the rate of RuBP carboxylation and producing more 3-PGA, which is then reduced to G3P. Higher CO2 also suppresses photorespiration — when CO2 is abundant relative to O2, Rubisco overwhelmingly favors its carboxylase activity. Because more 3-PGA is generated, both NADPH and ATP consumption actually increase, not decrease, as the Calvin cycle runs faster to process the additional substrate.
Q100. Carotenoids and chlorophyll b serve as accessory pigments in the chloroplast antenna complexes. Which of the following best explains how they contribute to the light reactions?
Accessory pigments in the antenna complexes absorb photons at wavelengths chlorophyll a does not capture efficiently — for example, carotenoids absorb blue-green light, broadening the usable light spectrum. The absorbed energy is transferred via resonance energy transfer to the P680 or P700 reaction center chlorophylls, which then drive electron transport. Reaction centers always contain specialized chlorophyll a molecules; accessory pigments serve as antennas, not replacements. Water splitting is performed by the oxygen-evolving complex at PSII, not by accessory pigments. NADP+ reduction occurs at PSI, not at antenna pigments.
Q101. When yeast cells are deprived of oxygen, they carry out alcohol fermentation, converting pyruvate to ethanol and CO2. What is the essential metabolic function of this fermentation pathway?
Fermentation itself produces no ATP — all ATP under anaerobic conditions is generated by glycolysis. The essential function of fermentation is to oxidize NADH back to NAD+. During glycolysis, NAD+ is required to accept electrons during the oxidation of glyceraldehyde-3-phosphate. If NADH cannot be reoxidized, the cell runs out of NAD+ and glycolysis halts. Fermentation transfers electrons from NADH to pyruvate (or its derivative acetaldehyde), regenerating the NAD+ needed to keep glycolysis running. The Krebs cycle requires mitochondrial function and does not operate anaerobically in yeast.
Q102. Gram for gram, dietary fats yield more ATP than carbohydrates when completely oxidized in cellular respiration. Which of the following best explains this difference?
Fatty acids have a high hydrogen-to-oxygen ratio — their carbons carry more electrons in C-H bonds compared to carbohydrate carbons, which already bear oxygen atoms. When fatty acids are oxidized through beta-oxidation and the Krebs cycle, this greater degree of reduction means significantly more NADH and FADH2 are produced per carbon. These electron carriers deliver more electrons to the ETC, driving more proton pumping and greater ATP synthesis. Fats contain no phosphate groups and are nitrogen-free; they also require conversion to acetyl-CoA through beta-oxidation before entering the Krebs cycle.
Q103. Dinitrophenol (DNP) is a lipid-soluble molecule that carries protons across the inner mitochondrial membrane independently of ATP synthase. Which of the following would be expected in cells treated with DNP?
DNP is a proton ionophore that continuously dissipates the proton-motive force without coupling it to ATP synthesis. With the gradient drained, ATP production via oxidative phosphorylation drops dramatically. The cell, sensing critically low ATP, increases metabolic activity — the ETC runs faster (because back-pressure from the gradient is relieved) and consumes more NADH, FADH2, and O2. Energy is released as heat rather than captured as ATP, which is why DNP causes dangerous hyperthermia. ATP synthase activity actually decreases because it has no gradient to drive it, despite the faster ETC.
Q104. During cyclic electron flow in the chloroplast, electrons excited from Photosystem I are returned to the electron transport chain rather than used to reduce NADP+. What does cyclic electron flow produce?
In cyclic electron flow, electrons from excited P700 pass to ferredoxin and are redirected back through the cytochrome b6f complex, which pumps protons into the thylakoid lumen. This proton gradient drives ATP synthesis via ATP synthase. Because electrons cycle back to P700 rather than reducing NADP+, no NADPH is produced. Because Photosystem II is not involved, water is not split and no oxygen is released. Cyclic flow helps balance the chloroplast's ATP-to-NADPH ratio when the Calvin cycle requires more ATP than the linear pathway alone provides.
Q105. A researcher measures CO2 production from yeast cultures at 10°C, 25°C, 37°C, and 50°C. Respiration rate peaks at 37°C and falls sharply at 50°C. Which explanation best accounts for the drop at 50°C?
Enzymes function optimally within a specific temperature range. Above the optimum, excess thermal energy disrupts the weak noncovalent bonds — hydrogen bonds, ionic interactions, and hydrophobic interactions — that maintain the enzyme's three-dimensional shape. This denaturation distorts the active site, preventing substrate binding and catalysis. At 50°C, glycolytic enzymes and Krebs cycle enzymes in yeast lose function, sharply reducing respiration. In a well-designed experiment, glucose is not limiting. Alcohol fermentation in yeast still produces CO2 from pyruvate decarboxylation, so a switch to fermentation would not explain a drop in CO2 output.
Q106. In the Calvin cycle, how many molecules of CO2 must be fixed by Rubisco to produce one net molecule of glyceraldehyde-3-phosphate (G3P) that exits the cycle?
Each turn of the Calvin cycle fixes one CO2. After three turns (fixing three CO2 molecules), six G3P molecules are produced from six 3-PGA molecules. Five of those six G3P molecules must be used to regenerate three RuBP molecules — only one G3P is available as net output. Therefore, three CO2 fixation events yield one net G3P. Six CO2 molecules (six turns) are needed to produce enough G3P to synthesize one glucose. Choosing 1 or 2 ignores the cost of RuBP regeneration, which consumes most of the G3P produced.
Q107. What is the primary function of coenzyme A (CoA) during the conversion of pyruvate to acetyl-CoA?
During pyruvate oxidation, the pyruvate dehydrogenase complex removes a carbon as CO2, oxidizes the remaining 2-carbon unit, and covalently attaches it to CoA via a thioester bond, forming acetyl-CoA. CoA functions as a molecular carrier, delivering the acetyl group to the Krebs cycle, where it condenses with oxaloacetate to form citrate. NAD+ accepts the electrons released during pyruvate oxidation (producing NADH), but this is performed by the enzyme complex itself. CoA is released when the acetyl group is transferred to oxaloacetate, allowing CoA to be reused.
Q108. On a hot, dry day, a C3 plant closes its stomata to limit water loss. Which of the following is a direct metabolic consequence inside the mesophyll cells?
When stomata close, CO2 cannot enter the leaf and O2 produced by photosynthesis cannot escape. As CO2 is consumed by Rubisco and O2 accumulates, the intracellular O2-to-CO2 ratio increases significantly. Rubisco is a bifunctional enzyme: at high O2 concentrations relative to CO2, it acts as an oxygenase instead of a carboxylase, binding O2 and initiating photorespiration — a wasteful process that releases CO2 without producing sugar. The Calvin cycle slows, not accelerates, due to CO2 substrate limitation. Water splitting at PSII responds to light intensity, not CO2 levels.
Q109. DCMU (diuron) is a herbicide that blocks the plastoquinone-binding site on Photosystem II, preventing electron transfer from PSII to the plastoquinone pool. In an illuminated leaf treated with DCMU, which outcome is most likely?
DCMU blocks the linear electron transport chain at PSII, preventing electrons from reaching plastoquinone. Without electrons flowing through the cytochrome b6f complex and plastocyanin, PSI cannot receive replacement electrons via the linear pathway, so NADP+ reduction stops and water-splitting-derived electrons cannot reach PSI. However, PSI can independently perform cyclic electron flow: excited electrons from P700 pass to ferredoxin and cycle back through cytochrome b6f to plastocyanin and back to P700, pumping protons and generating ATP without producing NADPH or O2. Choice A is wrong because the linear chain linking PSII to PSI is broken. Light absorption at PSI and PSII occurs independently of water splitting.
Q110. A researcher measures net carbon fixation rate and water-use efficiency (CO2 fixed per unit of water lost) as stomatal aperture progressively decreases from fully open to fully closed. Which finding would best support the hypothesis that partial stomatal closure is metabolically advantageous during mild water stress?
Water-use efficiency (WUE) is the ratio of CO2 fixed to water lost. As stomata partially close, transpiration decreases more steeply than CO2 uptake because water vapor exits rapidly along a steep concentration gradient, while CO2 can still diffuse in through a narrower aperture along a shallower gradient. This temporarily improves WUE — the plant conserves more water per unit of carbon gained. However, at full closure, no CO2 enters and fixation approaches zero, causing WUE to collapse entirely. This explains why plants evolved fine-tuned stomatal regulation rather than a simple all-or-nothing closing response to water stress.
Q111. A researcher isolates intact, functional chloroplasts and places them in a buffer solution containing NADP+ but lacking ADP and inorganic phosphate. The chloroplasts are illuminated with white light. Which outcome is most likely?
Electron transport through Photosystems II and I, water splitting, and NADP+ reduction are all driven directly by light energy and do not require ADP as a substrate. Therefore, O2 will still be released from water splitting and NADP+ will be reduced to NADPH. However, ATP synthase requires ADP as a phosphate acceptor — without ADP (and inorganic phosphate), ATP synthase cannot function and no ATP is synthesized. Without ATP, the Calvin cycle cannot regenerate RuBP or phosphorylate 3-PGA, so it cannot proceed. NADPH accumulates but cannot be consumed; once all NADP+ is reduced, further NADPH production also slows.
Q112. A researcher engineers a mutant mitochondrion in which the F0 channel subunit of ATP synthase is intact (protons can flow freely through it) but the F1 catalytic subunit cannot synthesize ATP. Which of the following best describes the metabolic outcome?
With F0 intact but F1 non-functional, protons flow continuously through F0 without driving ATP synthesis — mimicking a chemical uncoupler. Because protons leak through F0, the proton gradient is continuously dissipated and cannot build up, removing the back-pressure that normally limits ETC activity. The ETC therefore runs at an elevated rate, consuming more NADH, FADH2, and O2, releasing energy as heat. No ATP is generated by oxidative phosphorylation, though glycolysis and Krebs cycle substrate-level phosphorylation still function. The Krebs cycle may accelerate in response to low cellular ATP, but this cannot compensate for the near-complete loss of oxidative phosphorylation output.
Q113. FADH2 donates electrons to the electron transport chain at Complex II, while NADH donates electrons at Complex I. Oxidation of one NADH yields approximately 2.5 ATP, while one FADH2 yields approximately 1.5 ATP. Which explanation best accounts for this difference?
Both NADH and FADH2 donate two electrons to the ETC. The difference lies in the entry point. NADH electrons enter at Complex I, then proceed through Complex III and Complex IV — three proton-pumping complexes — translocating approximately 10 protons per electron pair. FADH2 electrons enter at Complex II, which does not pump protons; they then pass only through Complexes III and IV — two proton-pumping complexes — translocating approximately 6 protons per electron pair. Because fewer protons are pumped per FADH2, less proton-motive force is generated, driving less ATP synthesis. The inherent stability of FADH2 versus NADH is not the cause.
Q114. A researcher supplies a plant with radioactively labeled 14CO2 under continuous illumination and stops the experiment after only 5 seconds. In which organic molecule would the radioactive 14C label most likely appear at the highest concentration?
This mirrors the classic Calvin-Benson experiment. The first step of the Calvin cycle is Rubisco-catalyzed carboxylation: one CO2 combines with the 5-carbon RuBP to form an unstable 6-carbon intermediate that immediately splits into two molecules of 3-PGA, a stable 3-carbon compound. Within just 5 seconds, the label appears overwhelmingly in 3-PGA — the first stable product of carbon fixation. Glucose is a downstream product requiring multiple Calvin cycle turns and additional processing. RuBP already exists before CO2 fixation and would only be labeled after 3-PGA is processed and used to regenerate it. Acetyl-CoA is a product of cellular respiration, not the Calvin cycle.
Q115. Phosphofructokinase-1 (PFK-1), the key regulatory enzyme of glycolysis, is allosterically inhibited by high ATP concentrations and activated by high AMP concentrations. In which cellular scenario would PFK-1 inhibition most significantly slow glycolysis?
PFK-1 is inhibited when cellular energy charge is high — specifically when ATP is abundant and AMP is low. In a resting cell, ATP is plentiful (energy demand is minimal) and AMP is near zero, providing no signal to accelerate glycolysis. High ATP binds allosterically to PFK-1 at a regulatory site distinct from the active site, reducing its affinity for fructose-6-phosphate and slowing the pathway. During vigorous exercise (choice A), ATP is consumed rapidly and AMP builds up through the adenylate kinase reaction, strongly activating PFK-1. Cyanide poisoning (choice C) prevents oxidative phosphorylation and causes AMP accumulation, which also activates PFK-1. Low oxygen conditions (choice D) similarly signal high energy demand, keeping PFK-1 active.
Q116. In eukaryotic cells, where does glycolysis occur?
Glycolysis occurs in the cytosol and does not require membrane-bound organelles. This pathway functions under both aerobic and anaerobic conditions and is present in virtually all living cells. The mitochondrial matrix is where the Krebs cycle occurs, while the inner mitochondrial membrane houses the electron transport chain and ATP synthase.
Q117. Which molecule is commonly referred to as the primary energy currency of the cell because it directly powers most cellular work?
ATP (adenosine triphosphate) is the direct energy currency of the cell. When hydrolyzed to ADP and inorganic phosphate, the released free energy powers processes such as active transport, muscle contraction, and biosynthesis. NADH and FADH2 are electron carriers that store chemical energy but must first donate electrons to the electron transport chain before that energy can be converted to ATP; they do not directly power most cellular reactions.
Q118. Which two molecules are the primary products of the light-dependent reactions of photosynthesis that are directly consumed by the Calvin cycle?
The light-dependent reactions capture light energy and use it to produce ATP via photophosphorylation and NADPH via reduction of NADP+. These two molecules power the Calvin cycle to fix CO2 into G3P. Glucose is the downstream product of the Calvin cycle, not the light reactions. Oxygen is released as a byproduct of water splitting at Photosystem II but is not consumed by the Calvin cycle.
Q119. In eukaryotic cells, which organelle is the primary site of aerobic cellular respiration, housing both the Krebs cycle and the electron transport chain?
The mitochondrion is the primary site of aerobic respiration. The Krebs cycle runs in the mitochondrial matrix, and the electron transport chain along with ATP synthase is embedded in the inner mitochondrial membrane. Chloroplasts carry out photosynthesis. The nucleus houses genetic information, and the smooth endoplasmic reticulum is involved in lipid synthesis and detoxification.
Q120. Which photosynthetic pigment serves as the primary reaction-center pigment in both Photosystem I and Photosystem II, directly undergoing photoexcitation and initiating electron transfer?
Chlorophyll a is the primary reaction-center pigment. It is the molecule that directly absorbs photons, becomes excited, and passes high-energy electrons to the electron transport chain. Chlorophyll b, beta-carotene, and xanthophylls are accessory pigments that absorb light at different wavelengths and transfer the energy to chlorophyll a via resonance energy transfer, but they do not directly initiate photochemistry at the reaction center.
Q121. Starting with one molecule of glucose, what is the net yield of ATP from glycolysis alone?
Glycolysis produces 4 ATP by substrate-level phosphorylation but invests 2 ATP during the energy-requiring steps of the first half, giving a net yield of 2 ATP per glucose. The 36 to 38 figure represents the total ATP from complete aerobic respiration. The gross yield of 4 ATP is commonly confused with the net yield; the 2 ATP investment must be subtracted to get the net of 2.
Q122. The Calvin cycle (light-independent reactions) takes place in which compartment of the chloroplast?
The Calvin cycle occurs in the stroma, the fluid-filled space surrounding the thylakoids inside the chloroplast. The enzymes of the cycle, including RuBisCO, are dissolved in the stroma. The thylakoid membranes host the light-dependent reactions. The granum is a stack of thylakoid discs and is part of the membrane system where light reactions occur, not where the Calvin cycle takes place.
Q123. During chemiosmosis in mitochondria, protons flow from the intermembrane space through ATP synthase into the matrix. What is the driving force for this proton movement?
Proton movement through ATP synthase is driven by the proton motive force, which has two components: a pH gradient (higher H+ concentration in the intermembrane space than the matrix) and an electrical gradient (positive charge outside, negative inside). Energy released as protons flow passively down this electrochemical gradient drives conformational changes in ATP synthase that catalyze phosphorylation of ADP. This is facilitated diffusion through ATP synthase, not active transport; NADH oxidation at Complex I builds the gradient rather than directly powering this step.
Q124. Oligomycin is an antibiotic that physically blocks the proton channel of the Fo subunit of mitochondrial ATP synthase. In cells treated with oligomycin, which of the following outcomes would be expected?
Blocking ATP synthase prevents protons from flowing back into the matrix, causing the proton gradient across the inner membrane to become extremely steep. This back-pressure makes it increasingly difficult for the ETC complexes to pump additional protons against the high gradient, slowing and eventually halting electron transport. Consequently, both electron transport and ATP production decrease together. This contrasts with uncouplers such as DNP, which dissipate the gradient and accelerate electron transport while reducing ATP yield.
Q125. C4 plants have a competitive advantage over C3 plants in hot, sunny environments primarily because they:
In C4 plants, PEP carboxylase in mesophyll cells fixes CO2 into four-carbon organic acids such as malate or oxaloacetate. These are transported to bundle sheath cells where CO2 is released at high local concentrations, saturating RuBisCO and outcompeting O2. This minimizes photorespiration, which wastes energy by consuming O2 and releasing CO2 without producing sugar. C4 plants still use the Calvin cycle in bundle sheath cells. Nighttime stomatal opening is the strategy of CAM plants, not C4 plants.
Q126. Which of the following correctly describes the role of molecular oxygen in aerobic cellular respiration?
At Complex IV (cytochrome c oxidase), electrons arriving from cytochrome c are transferred to molecular oxygen, which is reduced to water: O2 + 4H+ + 4e- forms 2H2O. Oxygen is the terminal electron acceptor and is itself reduced, not oxidized, in this reaction. It does not participate in substrate-level phosphorylation; those reactions use phosphorylated organic intermediates. Oxygen does not interact with electrons at Complex I.
Q127. A researcher adds antimycin A, a drug that specifically inhibits the cytochrome bc1 complex (Complex III) of the electron transport chain. What would be the most direct consequence of this inhibition?
Complex III transfers electrons from ubiquinol (QH2) to cytochrome c. Antimycin A blocks this step, so cytochrome c cannot be reduced. Without reduced cytochrome c, Complex IV cannot function, and oxygen cannot serve as the final electron acceptor. The entire downstream portion of the chain halts, and the effects propagate upstream as ubiquinone accumulates in its reduced form. Protons are not pumped in reverse by the inhibited complex; inhibition simply stops forward proton pumping at that site.
Q128. During the Krebs cycle, isocitrate is oxidatively decarboxylated by isocitrate dehydrogenase, releasing CO2. Which molecule directly accepts the electrons removed in this oxidation step?
Isocitrate dehydrogenase oxidizes isocitrate to alpha-ketoglutarate and releases CO2. The two electrons and one proton removed in this oxidation are transferred directly to NAD+, reducing it to NADH. FAD is reduced to FADH2 by succinate dehydrogenase (Complex II) in a different step of the cycle. Molecular oxygen is not involved in Krebs cycle reactions, and coenzyme A carries acyl groups rather than electrons.
Q129. In photorespiration, RuBisCO binds O2 instead of CO2, initiating the oxygenase reaction. Which of the following best explains why photorespiration is considered energetically costly to C3 plants?
When RuBisCO oxygenates RuBP, it produces one molecule of 3-phosphoglycerate and one of 2-phosphoglycolate. The 2-phosphoglycolate must be salvaged through the photorespiratory pathway spanning the chloroplast, peroxisome, and mitochondrion. This process consumes ATP and NADPH and releases CO2 that was previously fixed, representing a net loss of carbon and energy with no additional sugar output. RuBisCO is not permanently inactivated; the Calvin cycle does not run in reverse; and chlorophyll is not destroyed by photorespiration.
Q130. Which of the following correctly distinguishes substrate-level phosphorylation from oxidative phosphorylation?
In substrate-level phosphorylation, an enzyme directly transfers a phosphate group from a phosphorylated organic substrate to ADP, as in the phosphoglycerate kinase and pyruvate kinase reactions of glycolysis and the succinyl-CoA synthetase reaction of the Krebs cycle. Oxidative phosphorylation uses the proton gradient built by the electron transport chain to drive ATP synthase. The numbers in choice D are reversed: substrate-level phosphorylation yields only about 4 ATP equivalents per glucose (2 from glycolysis, 2 from the Krebs cycle), while oxidative phosphorylation accounts for the majority of ATP produced.
Q131. CAM plants such as cacti fix CO2 into organic acids at night and release it for the Calvin cycle during the day. What is the primary advantage of this temporal separation of CO2 uptake and carbon fixation?
CAM plants open their stomata at night when temperatures are lower and humidity higher, greatly reducing evaporative water loss. CO2 is fixed by PEP carboxylase into malate, which is stored in vacuoles. During the hot, dry day, stomata remain closed to conserve water; malate is decarboxylated, releasing CO2 for RuBisCO and the Calvin cycle, which are powered by the daytime light reactions. Light reactions still require sunlight; RuBisCO is still used in the Calvin cycle; and CO2 fixation reactions do not generate ATP independently of the light reactions.
Q132. When muscle cells are deprived of oxygen during intense exercise, they convert pyruvate to lactate via lactic acid fermentation. What is the primary metabolic purpose of this pyruvate-to-lactate conversion?
Lactic acid fermentation does not produce additional ATP. Instead, it regenerates NAD+ by transferring electrons from NADH to pyruvate, forming lactate and NAD+. This regenerated NAD+ is essential because glycolysis requires NAD+ as an electron acceptor at the glyceraldehyde-3-phosphate dehydrogenase step. Without NAD+ regeneration, glycolysis would halt for lack of oxidized electron carrier, and the cell would produce no ATP at all. Pyruvate is converted to acetyl-CoA by pyruvate dehydrogenase only under aerobic conditions, not during fermentation.
Q133. A researcher identifies a loss-of-function mutation in succinyl-CoA synthetase, the Krebs cycle enzyme that converts succinyl-CoA to succinate while producing one GTP. What would be the most significant metabolic consequence of this mutation?
If succinyl-CoA cannot be converted to succinate, succinyl-CoA accumulates and the Krebs cycle stalls at this step. The downstream reactions that generate NADH (from malate dehydrogenase) and FADH2 (from succinate dehydrogenase) cannot proceed, dramatically reducing the substrates available for the electron transport chain. This loss far outweighs the direct loss of only 2 GTP per glucose mentioned in choice A. GTP does not power proton pumping in the ETC. Glycolysis cannot generate enough ATP to compensate for the near-complete loss of oxidative phosphorylation.
Q134. A researcher measures the P/O ratio (moles of ATP produced per oxygen atom consumed) in isolated mitochondria using either NADH-linked substrates such as malate or FADH2-linked substrates such as succinate. The P/O ratio is consistently lower with succinate than with malate. Which of the following best explains this difference?
NADH donates electrons to Complex I, which pumps 4 protons per pair of electrons into the intermembrane space. FADH2 donates electrons to Complex II (succinate dehydrogenase), which transfers electrons to ubiquinone but does not pump any protons. Both substrates then proceed through Complexes III and IV, which pump approximately 4 and 2 protons respectively. Total proton translocation is about 10 per NADH (roughly 2.5 ATP) versus 6 per FADH2 (roughly 1.5 ATP), explaining the lower P/O ratio. Complex II never reverses its proton pumping, and oxygen consumption per electron pair is identical for both substrates.
Q135. A C3 plant grown in normal air (approximately 0.04% CO2, 21% O2) is shifted to an atmosphere of elevated CO2 (1% CO2) and reduced O2 (5%). Compared to normal conditions, which of the following changes in photosynthetic metabolism would you predict?
RuBisCO uses CO2 and O2 as competing substrates at the same active site; their relative concentrations determine which reaction dominates. When CO2 concentration rises dramatically and O2 falls, CO2 overwhelmingly wins the competition, suppressing the oxygenase reaction and thus photorespiration. With more CO2 substrate and less energy wasted on photorespiratory salvage, the carboxylase reaction and Calvin cycle output increase. RuBisCO kinetics are concentration-dependent. No compensatory mechanism forces more O2 binding when CO2 rises; the relationship is purely competitive.
Q136. A researcher engineers a mutant mitochondrion in which Complex I can still transfer electrons from NADH to ubiquinone but has completely lost the ability to pump protons across the inner membrane. Which prediction about ATP production in this mutant is most accurate?
Complex I normally pumps 4 protons per electron pair. If this pumping is abolished while electron transfer continues, NADH-derived electrons still flow to ubiquinone and onward through Complexes III and IV. Complexes III and IV retain their proton-pumping capacity, contributing approximately 4 and 2 protons per electron pair respectively. This smaller proton gradient still drives ATP synthase, so some oxidative phosphorylation continues. Complete elimination of ATP would require blocking the entire ETC or ATP synthase. Ubiquinone carries electrons between complexes and does not directly interact with ATP synthase.
Q137. In a classic experiment, isolated thylakoid membranes were equilibrated in a pH 4 buffer to acidify their interior, then rapidly transferred to a pH 8 buffer containing ADP and inorganic phosphate. ATP synthesis was detected in complete darkness with no added electron donors. What conclusion is best supported by this result?
This experiment demonstrates that the proton gradient itself, not light energy directly, drives ATP synthase. By artificially creating a pH gradient (low pH inside the thylakoid, high pH outside), protons flow down their concentration gradient through ATP synthase, generating ATP in complete darkness without any electron transport. This was powerful evidence for the chemiosmotic hypothesis: energy is stored as an electrochemical gradient and converted to ATP by the synthase. The Calvin cycle requires both ATP and NADPH and cannot run on a pH gradient alone. Electron transport was entirely absent in this experimental setup.
Q138. Malonate is a structural analog of succinate that competitively inhibits succinate dehydrogenase (Complex II). In isolated mitochondria actively oxidizing both NADH-linked and FADH2-linked substrates, adding malonate would most accurately produce which outcome?
Complex II oxidizes FADH2 produced in the Krebs cycle and transfers those electrons to ubiquinone. Malonate blocks this step, so FADH2-derived electrons cannot enter the electron transport chain. However, Complex I is unaffected and continues to oxidize NADH, still reducing ubiquinone and sustaining electron flow through Complexes III and IV. The overall proton gradient is maintained but reduced, yielding fewer ATP per glucose. Complex I cannot increase output beyond its substrate availability to compensate. The Krebs cycle can still produce NADH at steps upstream of the succinate dehydrogenase reaction; it does not halt completely.
Q139. A researcher exposes a plant to a single brief flash of bright light and then immediately places it in complete darkness. Sensitive instruments detect that CO2 fixation continues at a measurable rate for a short period after the flash before stopping entirely. Which explanation best accounts for this observation?
Calvin cycle enzymes do not require light as a direct cofactor. During the flash, the light reactions produce a finite pool of ATP and NADPH. The Calvin cycle uses these molecules to fix CO2 into G3P and regenerate RuBP. Once that stored pool of ATP and NADPH is exhausted, the cycle stalls because no new supply is generated in darkness, even though the enzymes remain intact. RuBisCO is not irreversibly inactivated by darkness; it undergoes regulatory modifications such as carbamylation and thioredoxin-mediated changes, but the primary immediate limiting factor is substrate depletion. Stomatal responses to light are too slow to explain this rapid effect.
Q140. A researcher discovers a plant mutant in which the cytochrome b6f complex, which links electron output from Photosystem II to Photosystem I, is completely nonfunctional. Which of the following best predicts the metabolic consequences for this plant's light reactions?
The cytochrome b6f complex accepts electrons from plastoquinol (PQH2, produced by PSII) and passes them to plastocyanin, which delivers them to PSI. Without b6f, electrons from PSII cannot reach PSI; NADP+ cannot be reduced to NADPH, eliminating the reducing power needed for the Calvin cycle. The b6f complex also pumps protons into the thylakoid lumen, contributing significantly to the proton gradient for ATP synthesis. Critically, cyclic electron flow also requires b6f, since electrons cycle from ferredoxin back through plastoquinone and then through b6f before returning to PSI. Choice D is doubly wrong: b6f is needed for cyclic flow, and cyclic flow does not produce NADPH regardless.
Q141. Which of the following correctly describes the molecular structure of ATP?
ATP (adenosine triphosphate) consists of the nitrogenous base adenine, the 5-carbon sugar ribose, and three phosphate groups. Energy is released primarily by hydrolyzing the bond between the second and third phosphate groups. Using deoxyribose would make the molecule a DNA nucleotide derivative. ADP has only two phosphate groups, and guanine is the base found in GTP, not ATP.
Q142. In a eukaryotic cell, in which cellular compartment does glycolysis occur?
Glycolysis occurs in the cytoplasm and does not require mitochondria, which is why it can proceed under both aerobic and anaerobic conditions. The mitochondrial matrix is the site of the Krebs cycle, the inner mitochondrial membrane houses the electron transport chain and ATP synthase, and the chloroplast stroma is where the Calvin cycle takes place.
Q143. Which of the following are direct products of the light-dependent reactions of photosynthesis?
The light-dependent reactions capture light energy to produce ATP and NADPH (used to power the Calvin cycle) and release O2 as a byproduct of water splitting at the oxygen-evolving complex. Glucose is a downstream product of the Calvin cycle. G3P and RuBP are intermediates of the Calvin cycle. CO2 is a substrate consumed in the Calvin cycle, not a product of the light reactions.
Q144. Which molecules must be supplied as inputs to the Calvin cycle for carbon fixation and reduction to proceed?
The Calvin cycle requires CO2 (the carbon substrate fixed by RuBisCO), ATP (to drive phosphorylation steps), and NADPH (to reduce 3-phosphoglycerate to G3P). H2O and sunlight are consumed by the light reactions to generate ATP and NADPH, not used directly in the Calvin cycle. NADH and FADH2 are electron carriers produced in cellular respiration, not photosynthesis.
Q145. What is the primary metabolic purpose of fermentation under anaerobic conditions?
Fermentation regenerates NAD+ by transferring electrons from NADH to an organic acceptor — pyruvate in lactic acid fermentation and acetaldehyde in alcoholic fermentation. Without this regeneration, glycolysis would halt because NAD+ is required as an electron acceptor for glyceraldehyde-3-phosphate dehydrogenase. Fermentation itself produces no additional ATP; all 2 net ATP come from glycolysis alone. Converting pyruvate to acetyl-CoA requires the pyruvate dehydrogenase complex and occurs only under aerobic conditions.
Q146. Which wavelengths of visible light does chlorophyll a absorb most strongly?
Chlorophyll a has absorption peaks near 430 nm (blue-violet) and 680 nm (red). Green and yellow wavelengths (500-600 nm) are largely reflected, which is why leaves appear green to our eyes. Ultraviolet light is mostly absorbed by the ozone layer and is not efficiently used by chlorophyll a, and far-red wavelengths above 700 nm are outside the effective range for standard photochemistry in Photosystem II.
Q147. How many net ATP molecules are produced by substrate-level phosphorylation during glycolysis of a single glucose molecule?
Glycolysis generates 4 ATP by substrate-level phosphorylation (at the phosphoglycerate kinase and pyruvate kinase steps) but consumes 2 ATP in the preparatory phase (at the hexokinase and phosphofructokinase-1 steps), yielding a net gain of 2 ATP per glucose. The 4 NADH produced are used in the electron transport chain under aerobic conditions. Values near 30-32 ATP represent the total yield from complete aerobic respiration, not glycolysis in isolation.
Q148. In aerobic cellular respiration, what role does molecular oxygen (O2) play?
Oxygen accepts the electrons that have traveled through the electron transport chain and combines with protons to form water, a reaction catalyzed by Complex IV (cytochrome c oxidase): O2 + 4H+ + 4e- → 2H2O. This keeps the ETC running by continuously accepting electrons. Oxygen is not involved in glycolysis, does not directly phosphorylate ADP, and is not a cofactor for ATP synthase. Its role as the terminal electron acceptor is essential for maintaining the proton gradient that drives ATP synthesis.
Q149. C4 plants spatially separate carbon fixation between mesophyll cells and bundle-sheath cells. Which of the following best explains the adaptive advantage of this arrangement?
In C4 plants, PEP carboxylase in mesophyll cells fixes CO2 into 4-carbon organic acids (oxaloacetate, then malate or aspartate). These are shuttled to bundle-sheath cells and decarboxylated, releasing CO2 in high concentrations near RuBisCO. This suppresses the competing oxygenase reaction that initiates photorespiration. PEP carboxylase has no oxygenase activity and a very high affinity for CO2, making it ideal for initial fixation. The Calvin cycle in bundle-sheath cells still requires ATP and NADPH from light reactions.
Q150. During oxidative phosphorylation, protons flow from the intermembrane space into the mitochondrial matrix through ATP synthase. What is the direct driving force for this proton flow?
The electron transport chain pumps protons from the matrix into the intermembrane space, creating a proton motive force (PMF) with two components: a concentration gradient (higher [H+] in the intermembrane space) and an electrical potential (positive outside, negative inside). Protons flow down this combined electrochemical gradient through ATP synthase, and the energy released drives rotation of the enzyme and ATP synthesis. NADH is oxidized by Complex I — it is not hydrolyzed. There is no direct electron transfer from FADH2 to ADP.
Q151. Phosphofructokinase-1 (PFK-1), the primary regulatory enzyme of glycolysis, is inhibited by high concentrations of ATP and activated by high concentrations of AMP. This regulatory pattern is best described as:
ATP and AMP bind to regulatory sites distinct from the active site (which binds fructose-6-phosphate), making their effects allosteric rather than competitive. High ATP signals energy surplus and slows glycolysis; high AMP signals energy deficit and accelerates it. This is reversible and operates at the protein level — not through changes in gene expression, which would be far too slow to respond to rapid shifts in energy demand. This is a classic example of feedback inhibition matching metabolic flux to cellular need.
Q152. During pyruvate oxidation, which of the following correctly describes the fate of each pyruvate molecule entering the mitochondrial matrix?
The pyruvate dehydrogenase complex catalyzes oxidative decarboxylation of pyruvate (3 carbons): one carbon is lost as CO2, the electrons from this oxidation reduce NAD+ to NADH, and the remaining 2-carbon unit is attached to coenzyme A to form acetyl-CoA. No ATP is produced at this step, no FADH2 is generated, and the full 3-carbon pyruvate does not enter the Krebs cycle intact — only the 2-carbon acetyl group does.
Q153. Which of the following correctly distinguishes Photosystem II from Photosystem I based on their primary functions in linear electron flow?
In linear (non-cyclic) electron flow, Photosystem II uses absorbed light to oxidize water (releasing O2 and H+) and excite electrons to a higher energy level. These electrons pass through the plastoquinone pool, cytochrome b6f complex, and plastocyanin to Photosystem I. There, a second photon re-energizes them so they can be passed to ferredoxin and then to NADP+ reductase, producing NADPH. Photosystem II has a P680 reaction center and Photosystem I has a P700 reaction center — not the reverse. Neither photosystem directly synthesizes ATP.
Q154. Complete aerobic respiration of one glucose molecule yields approximately 30-32 ATP, while anaerobic fermentation of the same glucose yields only 2 ATP. Which of the following best explains this large difference?
Glycolysis yields 2 net ATP, and the Krebs cycle adds 2 more by substrate-level phosphorylation. The remaining 26-28 ATP come from oxidative phosphorylation: the 10 NADH and 2 FADH2 produced per glucose donate electrons to the electron transport chain, driving proton pumping and subsequent ATP synthesis via chemiosmosis. Fermentation bypasses the Krebs cycle and ETC entirely. Fermentation does not consume ATP to regenerate NAD+; electrons from NADH are simply transferred to organic acceptors without any ATP expenditure.
Q155. In cyclic electron flow around Photosystem I, electrons return from ferredoxin to the plastoquinone pool rather than reducing NADP+. What is the primary outcome of this pathway?
In cyclic electron flow, electrons from excited Photosystem I pass to ferredoxin and then back to the plastoquinone pool, where they continue driving proton pumping across the thylakoid membrane. This generates additional PMF and ATP without any net oxidation of water (so no O2 is released) and without any net reduction of NADP+ to NADPH. This is useful when the cell needs a higher ATP:NADPH ratio than linear flow provides, such as during active CO2 fixation in the Calvin cycle, which consumes 3 ATP and 2 NADPH per CO2 fixed.
Q156. Complete oxidation of a fatty acid yields more ATP per carbon than complete oxidation of glucose. Which of the following best explains this difference?
Fatty acids have a very high ratio of hydrogen to oxygen — they are far more reduced than glucose, which already contains many carbon-oxygen bonds. During beta-oxidation, each round of cleavage produces one NADH and one FADH2 in addition to an acetyl-CoA. Because each carbon in a fatty acid is more reduced, its oxidation transfers more electrons to NAD+ and FAD per carbon, yielding more electron carriers that feed the electron transport chain. Fatty acids do not contain phosphate groups and do not have a unique substrate-level phosphorylation step.
Q157. A cell experiencing severe hypoxia accumulates NADH, resulting in a very high NADH:NAD+ ratio. Which of the following physiological consequences is most directly predicted by this condition?
Several Krebs cycle enzymes — including isocitrate dehydrogenase, alpha-ketoglutarate dehydrogenase, and malate dehydrogenase — require NAD+ as an electron acceptor. When NAD+ is depleted and NADH accumulates, these reactions are product-inhibited and slow dramatically. Additionally, high NADH allosterically inhibits citrate synthase. ATP synthase is driven by the proton gradient, not by NADH directly. PFK-1 is regulated by ATP and AMP, not NADH. Pyruvate dehydrogenase is actually inhibited — not activated — by a high NADH:NAD+ ratio.
Q158. 2,4-dinitrophenol (DNP) is a lipid-soluble weak acid that can carry protons across the inner mitochondrial membrane independently of ATP synthase. Which of the following correctly predicts the effects of DNP treatment on mitochondrial function?
DNP uncouples electron transport from ATP synthesis by providing an alternative proton leak pathway. Protons that would normally flow through ATP synthase instead cycle across the membrane via DNP, dissipating the proton gradient as heat without producing ATP. Because the gradient collapses, the ETC experiences reduced back-pressure and runs faster, consuming more O2. The energy released by electron flow is converted to heat rather than stored in ATP. This mechanism was historically misused as a diet drug and caused fatal hyperthermia by converting metabolic energy entirely to heat.
Q159. The F1 subunit of ATP synthase synthesizes ATP through a rotary catalytic mechanism driven by proton flow through the F0 subunit. Which of the following best explains how rotation drives ATP synthesis at the molecular level?
Boyer's binding change mechanism (confirmed by Walker's crystal structures, earning a shared Nobel Prize) shows that the three beta subunits of F1 alternate through three conformational states: open (O, releases ATP), loose (L, binds ADP and Pi weakly), and tight (T, catalyzes ATP synthesis). Proton flow through F0 rotates the c-ring and the attached gamma subunit inside the fixed alpha/beta hexamer. This rotation mechanically drives each beta subunit through all three states sequentially. No direct phosphate transfer from lipids occurs, and centrifugal force is irrelevant at the molecular scale where thermal motion dominates.
Q160. A researcher measures the respiratory quotient (RQ = CO2 produced / O2 consumed) of a fasting mammal and finds a value of approximately 0.70. Which substrate is the animal primarily oxidizing, and what accounts for this RQ value?
For glucose (C6H12O6 + 6O2 → 6CO2 + 6H2O), RQ = 6/6 = 1.0. Fats have a much lower oxygen-to-carbon ratio than carbohydrates, so their complete oxidation requires more external O2 per CO2 released. A typical fatty acid like tripalmitin yields an RQ near 0.70. Fasting animals rely heavily on stored triglycerides, producing an RQ in this range. Protein catabolism yields an RQ near 0.80, not 0.70. The simple average of carbohydrate and fat RQ values does not equal 0.70 unless specific proportions are assumed.
Q161. The proton motive force (PMF) across the inner mitochondrial membrane has two components: an electrical potential (delta-psi) and a pH gradient (delta-pH). If an experiment selectively and completely collapses only the delta-pH component while leaving delta-psi intact, what is the most accurate prediction for ATP synthesis?
The PMF is the sum of both components: delta-psi (the membrane electrical potential, roughly 150-180 mV in mammalian mitochondria) and the contribution of delta-pH (equivalent to about 30-60 mV at physiological conditions). ATP synthase responds to total PMF — protons will continue to flow through it driven by the remaining electrical gradient, but at a reduced rate. ATP synthesis therefore continues at a lower rate rather than stopping entirely. Removing the pH gradient does not redirect additional proton flow through ATP synthase; it simply reduces total driving force.
Q162. In the Z-scheme, electrons traveling from Photosystem II to Photosystem I through the thylakoid electron transport chain lose energy that is used to pump protons. Light absorption at Photosystem I then re-energizes these electrons. Which of the following correctly explains the thermodynamic necessity of this second photon?
After electrons from Photosystem II travel through plastoquinone, cytochrome b6f, and plastocyanin, they arrive at the P700 reaction center of Photosystem I at a relatively low energy level (reduction potential near +0.4 V). Reducing NADP+ requires electrons at a more negative reduction potential (approximately -0.32 V). A second photon absorbed by P700 excites these electrons to a sufficiently high energy state that they can be passed to ferredoxin and ultimately reduce NADP+ via NADP+ reductase. Water splitting occurs at the oxygen-evolving complex of Photosystem II, not Photosystem I.
Q163. Oligomycin specifically blocks the F0 proton channel of ATP synthase, preventing proton flow through the enzyme. Compared to untreated mitochondria, which combination of results would be observed in oligomycin-treated mitochondria?
When oligomycin blocks the F0 proton channel, protons can no longer re-enter the matrix through ATP synthase. The ETC continues pumping protons initially, causing the gradient to build up (increases). This elevated back-pressure slows electron flow through the ETC because the proton pumps must work against a larger gradient, reducing O2 consumption. ATP synthesis falls because the proton channel is blocked. This contrasts with uncouplers like DNP, which also eliminate ATP synthesis but decrease the proton gradient by providing an alternative leak, causing O2 consumption to increase rather than decrease.
Q164. A plant is instantaneously transferred from bright light to complete darkness. In the seconds immediately following this transition, what is the most accurate description of Calvin cycle activity?
Calvin cycle enzymes do not directly absorb light — they require ATP and NADPH, which are supplied by the light reactions. When light is removed, ATP and NADPH production stops, but the existing pools are not instantaneously depleted. For a brief window of seconds, the Calvin cycle continues consuming the remaining ATP and NADPH until they are exhausted, at which point cycle activity slows and stops. Over a longer timescale (minutes), some Calvin cycle enzymes such as RuBisCO activase are also indirectly inactivated through the thioredoxin-ferredoxin system, which depends on reduced ferredoxin from Photosystem I. Light reactions do not compete with the Calvin cycle for CO2.
Q165. Under standard conditions, ATP hydrolysis releases approximately -30.5 kJ/mol. In actively metabolizing cells, the actual free energy released is often -50 kJ/mol or greater. Which of the following best explains this discrepancy?
The actual free energy of a reaction is given by delta-G = delta-G-naught + RT ln Q, where Q is the reaction quotient (products/reactants). In cells, metabolism continuously regenerates ATP while consuming ADP and Pi, maintaining Q far below the equilibrium value. This makes ln Q strongly negative, causing delta-G to be much more negative than the standard value of -30.5 kJ/mol. Enzymes lower activation energy but do not change the thermodynamic free energy of the overall reaction — they change kinetics, not thermodynamics. GTP hydrolysis is a separate reaction that does not add to the energy released by ATP hydrolysis. Chaperones do not alter bond energetics.
Q166. Which of the following best explains why ATP is considered a high-energy molecule?
The phosphoanhydride bonds linking the beta and gamma phosphate groups in ATP are high-energy because their hydrolysis products (ADP and inorganic phosphate) are stabilized by resonance and the relief of charge repulsion between adjacent negative phosphate groups, releasing approximately 30 kJ/mol under standard conditions. The adenine ring is not broken during ATP hydrolysis and is not the energy source. ATP does not accept electrons from NADH; instead, NADH donates electrons to the electron transport chain to ultimately drive ATP synthesis via chemiosmosis.
Q167. In eukaryotic cells, where does glycolysis occur?
Glycolysis occurs entirely in the cytosol and requires no membrane-bound organelles, which is why it can proceed under both aerobic and anaerobic conditions. The mitochondrial matrix is the site of the Krebs cycle and pyruvate oxidation. The inner mitochondrial membrane houses the electron transport chain complexes and ATP synthase. Because glycolysis is cytosolic, its NADH products cannot directly enter the mitochondrial matrix and must use shuttle systems to transfer their electrons.
Q168. Which molecules produced by the light reactions of photosynthesis are directly consumed to power the Calvin cycle?
The light reactions produce ATP via chemiosmosis across the thylakoid membrane and NADPH via the reduction of NADP+ at Photosystem I. Both molecules are consumed in the Calvin cycle: ATP provides phosphate groups and energy, while NADPH provides the reducing power needed to convert 3-phosphoglycerate (3-PGA) to glyceraldehyde-3-phosphate (G3P). Glucose is a downstream product of G3P, not an input. Carbon dioxide and water are overall reactants for photosynthesis, and ADP and NADP+ are the oxidized products returned from the Calvin cycle to the light reactions.
Q169. What is the net gain of ATP molecules produced during glycolysis from one molecule of glucose?
Glycolysis has two phases: an energy investment phase that consumes 2 ATP (to phosphorylate glucose and fructose-6-phosphate) and an energy payoff phase that produces 4 ATP via substrate-level phosphorylation, yielding a net gain of 2 ATP. The value of 32 ATP represents an estimate for total ATP from complete aerobic respiration of one glucose. The 4 ATP represents gross production before subtracting the 2 ATP investment, so it is not the net value.
Q170. What is the primary metabolic purpose of fermentation in eukaryotic cells under anaerobic conditions?
Fermentation regenerates NAD+ by using NADH to reduce pyruvate (to lactate or ethanol plus CO2). This is essential because the glyceraldehyde-3-phosphate dehydrogenase step in glycolysis requires NAD+ as an electron acceptor. Without NAD+ regeneration, glycolysis would halt and no ATP would be produced at all. Fermentation itself generates zero additional ATP; only glycolysis produces ATP under anaerobic conditions. Acetyl-CoA production from pyruvate is a separate aerobic process requiring pyruvate dehydrogenase.
Q171. In oxygenic photosynthesis, what molecule serves as the primary electron donor that replenishes electrons lost by Photosystem II?
Water is oxidized at the oxygen-evolving complex (OEC) associated with Photosystem II in a process called photolysis. The splitting of two water molecules provides four electrons to replace those ejected from the P680 reaction center by light energy, and releases four protons and one oxygen molecule as byproducts. NADPH is an electron carrier produced at Photosystem I, not a donor to PSII. Plastoquinone is the mobile electron carrier that accepts electrons from PSII and carries them to the cytochrome b6f complex.
Q172. What three-carbon molecule is the direct carbohydrate output of the Calvin cycle that serves as a precursor for glucose synthesis?
The Calvin cycle reduces 3-phosphoglycerate (3-PGA) using ATP and NADPH to produce glyceraldehyde-3-phosphate (G3P), a three-carbon sugar phosphate. G3P is the primary carbohydrate output and can be used to synthesize glucose, sucrose, starch, and other organic molecules. 3-PGA is an intermediate in the cycle that is reduced to form G3P, not the final export product. Pyruvate and acetyl-CoA are intermediates in cellular respiration, and oxaloacetate is a Krebs cycle intermediate.
Q173. RuBisCO catalyzes the carboxylation of ribulose-1,5-bisphosphate (RuBP) in the Calvin cycle. Why must the cycle complete three turns to yield one net molecule of G3P available for biosynthesis?
Each turn of the Calvin cycle incorporates one CO2 into one RuBP (5C), producing an unstable 6C intermediate that immediately splits into two molecules of 3-phosphoglycerate (3C each). Using ATP and NADPH, each 3-PGA is reduced to G3P. After three turns: 3 CO2 are fixed, yielding 6 molecules of G3P. Five of these six G3P molecules are required to regenerate the three RuBP molecules consumed in the next round, leaving only one net G3P for export. This stoichiometry, not RuBisCO's affinity, determines the three-turn requirement. RuBisCO's low CO2 affinity is a real limitation but is unrelated to why three turns are needed.
Q174. Which of the following correctly distinguishes substrate-level phosphorylation from oxidative phosphorylation?
Substrate-level phosphorylation directly couples the transfer of a phosphate group from a high-energy metabolic intermediate (such as 1,3-bisphosphoglycerate or phosphoenolpyruvate in glycolysis, or succinyl-CoA in the Krebs cycle) to ADP, forming ATP without a proton gradient. Oxidative phosphorylation uses the proton motive force created by the electron transport chain to drive ATP synthase. In reality, oxidative phosphorylation produces far more ATP (approximately 26-28 of the ~30 total per glucose) than substrate-level phosphorylation (4 total). Substrate-level phosphorylation does not require oxygen, which is why glycolysis can proceed anaerobically.
Q175. The inner mitochondrial membrane is extensively folded into structures called cristae. What is the primary functional significance of this folding?
The cristae dramatically expand the surface area of the inner mitochondrial membrane, allowing it to accommodate a much larger number of electron transport chain protein complexes (I through IV) and ATP synthase molecules than a smooth membrane of the same organelle size could support. More complexes mean more proton pumping and ATP synthesis capacity per mitochondrion. Glycolysis occurs in the cytosol, not in mitochondria. The inner membrane separates the matrix from the intermembrane space, not from the cytosol. Reducing matrix volume would decrease the space available for Krebs cycle reactions.
Q176. In C4 plants, CO2 is first fixed in mesophyll cells by PEP carboxylase and then transferred as a four-carbon acid to bundle sheath cells where the Calvin cycle occurs. What is the primary advantage of this spatial separation?
PEP carboxylase in mesophyll cells has a much higher affinity for CO2 than RuBisCO and does not react with O2. The four-carbon organic acids (malate or aspartate) produced are shuttled to bundle sheath cells, where they release CO2 via decarboxylation. This effectively pumps CO2 into bundle sheath cells, raising the local CO2 concentration around RuBisCO far above what would be achieved by passive diffusion from the atmosphere. High CO2 near RuBisCO suppresses its oxygenase activity, reducing photorespiration. C4 plants still require ATP and NADPH from light reactions and do not fix nitrogen. Stomata in C4 plants do open (though they can open less than in C3 plants due to higher water-use efficiency).
Q177. When a cell has a high ratio of ATP to ADP, which of the following responses would most likely occur in the regulation of cellular respiration?
A high ATP/ADP ratio signals that the cell's energy needs are currently satisfied. ATP acts as an allosteric inhibitor of key enzymes including phosphofructokinase-1 (PFK-1) in glycolysis and isocitrate dehydrogenase in the Krebs cycle, reducing their activity and slowing the entire catabolic pathway. This prevents wasteful overproduction of ATP. Isocitrate dehydrogenase is inhibited by ATP and activated by ADP and NAD+ (not activated when ATP is high). The electron transport chain rate is determined by substrate availability (NADH, FADH2, ADP) and slows when ADP is scarce relative to ATP.
Q178. For each acetyl-CoA molecule that enters the Krebs cycle, which of the following correctly summarizes the energy carriers and CO2 produced per single turn of the cycle?
Each turn of the Krebs cycle processes one two-carbon acetyl group and produces: 3 NADH (from the isocitrate dehydrogenase, alpha-ketoglutarate dehydrogenase, and malate dehydrogenase reactions), 1 FADH2 (from succinate dehydrogenase), 1 GTP or ATP (from succinyl-CoA synthetase via substrate-level phosphorylation), and 2 CO2 (released in the two decarboxylation steps). The four-carbon oxaloacetate acceptor is regenerated at the end of each turn. Only 2 CO2 are released per turn, not 1 or 3, because the two carbons entering as acetyl-CoA are oxidized at two distinct decarboxylation steps.
Q179. When O2 concentrations are high relative to CO2, RuBisCO can use O2 as a substrate in a process called photorespiration. Which of the following best describes why photorespiration is energetically costly for the plant?
When RuBisCO acts as an oxygenase, it splits RuBP into one three-carbon 3-PGA and one two-carbon phosphoglycolate. Phosphoglycolate cannot enter the Calvin cycle; it is processed through the photorespiratory pathway spanning chloroplasts, peroxisomes, and mitochondria. This pathway consumes ATP and reducing equivalents (NADH), and for every two phosphoglycolate molecules salvaged, one CO2 is released and only one 3-PGA is recovered. This represents a net loss of fixed carbon and an expenditure of ATP and reducing power. Hydrogen peroxide is produced in peroxisomes during photorespiration but is detoxified by catalase (not NADPH), so choice B describes an inaccurate mechanism.
Q180. NADH produced in the cytosol during glycolysis cannot directly cross the inner mitochondrial membrane. Depending on which shuttle system operates, cytosolic NADH effectively yields approximately 2.5 or 1.5 ATP. Which of the following best explains why the two shuttle systems yield different amounts of ATP?
The malate-aspartate shuttle regenerates mitochondrial NADH inside the matrix; these electrons enter at Complex I, allowing all three proton-pumping complexes (I, III, and IV) to contribute to ATP synthesis for a yield of approximately 2.5 ATP. The glycerol-3-phosphate shuttle transfers cytosolic NADH electrons to FAD on the inner mitochondrial membrane surface (via mitochondrial glycerol-3-phosphate dehydrogenase), producing FADH2 that feeds electrons directly into ubiquinone, bypassing Complex I and its proton pumping. This yields only approximately 1.5 ATP. Neither shuttle directly pumps protons; the difference arises entirely from where electrons enter the chain.
Q181. At low light intensities, increasing light intensity proportionally increases the rate of photosynthesis in a C3 plant. However, above a certain light intensity (the light saturation point), further increases do not raise the photosynthetic rate. Which of the following best explains this observation?
At low light intensities, the light reactions are the limiting factor: more photons produce more ATP and NADPH. Once the light reactions are saturated and producing ATP and NADPH faster than the Calvin cycle can consume them, the bottleneck shifts to the enzymatic steps of the Calvin cycle — primarily RuBisCO kinetics and CO2 availability. Adding more light beyond this point generates excess reducing power that the Calvin cycle cannot process, so the rate plateaus. In most plants, stomata open in light (not close), driven by guard cell responses to light and CO2 depletion. High light does not collapse the proton gradient; photodamage to reaction centers can occur under extreme conditions but is unrelated to the saturation curve.
Q182. In the mitochondrial electron transport chain, electrons flow from NADH through a series of protein complexes to the final electron acceptor, molecular oxygen. This electron flow is thermodynamically spontaneous primarily because:
Electrons flow spontaneously from carriers with more negative (lower) standard reduction potentials to those with more positive (higher) potentials. NADH has a reduction potential of approximately -0.32 V, meaning it readily donates electrons. The O2/H2O half-reaction has a reduction potential of approximately +0.82 V, meaning oxygen strongly attracts electrons. The large positive difference in reduction potential (delta E approximately 1.14 V) corresponds to a large release of free energy (approximately -220 kJ per mole of NADH), which is harnessed to pump protons and ultimately synthesize ATP. No ATP is consumed to drive electron flow; ATP is the product. Choice D inverts the correct logic: higher affinity for electrons means higher reduction potential, and that describes O2, not NADH.
Q183. A researcher measures net photosynthesis in a C3 plant at 25°C and then at 40°C, keeping all other variables constant. Which of the following best predicts and explains the outcome?
In C3 plants at elevated temperatures, two interacting effects reduce net photosynthesis: first, as temperature rises, the solubility of CO2 decreases more rapidly than that of O2, shifting the CO2/O2 ratio at RuBisCO's active site and favoring its oxygenase activity — greatly increasing photorespiration and its associated carbon and energy losses. Second, Calvin cycle enzymes (including RuBisCO activase) begin losing activity as temperatures approach their denaturation range near 40°C. While light reactions are relatively temperature-insensitive (they involve photophysical events), the overall rate of net photosynthesis is limited by Calvin cycle efficiency, which declines at high temperature in C3 plants.
Q184. Comparing the oxidation of NADH versus FADH2 by the mitochondrial electron transport chain, FADH2 yields fewer ATP molecules per mole oxidized. Which of the following correctly explains the molecular basis for this difference?
NADH donates its electrons to Complex I (NADH dehydrogenase), which pumps 4 protons across the inner mitochondrial membrane, then electrons continue through Complexes III and IV (pumping 4 and 2 protons respectively), yielding approximately 10 protons total and approximately 2.5 ATP. FADH2 (from succinate dehydrogenase or beta-oxidation) donates electrons directly to ubiquinone via Complex II, bypassing Complex I entirely. Without Complex I's 4-proton contribution, only approximately 6 protons are pumped, yielding approximately 1.5 ATP. Choice C is incorrect: FADH2 actually has a higher (more positive) standard reduction potential than NADH, not lower. Complexes III and IV pump the same number of protons regardless of electron origin, so choice D is also incorrect.
Q185. CAM plants open their stomata at night to fix CO2 as malate stored in vacuoles. During the day, stomata close and the stored malate is decarboxylated to supply CO2 to the Calvin cycle. Which of the following best describes a significant metabolic tradeoff inherent in the CAM strategy?
The CAM strategy is optimized for water conservation: closing stomata during the day drastically reduces transpiration water loss, which is critical in arid environments. However, this comes at the cost of limiting total CO2 uptake to nighttime hours when no light is available for the light reactions. CO2 can only be stored as malate, capping the maximum daytime carbon supply. As a result, CAM plants typically have substantially lower maximum photosynthetic rates and slower growth compared to C3 or C4 plants when water is not limiting. CAM plants do possess functional RuBisCO and perform the Calvin cycle normally during the day. PEP carboxylase functions across a range of temperatures and is not restricted to hot climates. Phosphate is recycled normally through metabolic pathways and is not irreversibly depleted.
Q186. DCMU is an herbicide that blocks the QB plastoquinone-binding site on Photosystem II, preventing electron transfer from PSII to the plastoquinone pool. A researcher treats isolated chloroplasts with DCMU. Which of the following correctly predicts the effect on non-cyclic and cyclic photophosphorylation?
Non-cyclic photophosphorylation requires both PSII and PSI: electrons flow from water to PSII, then through the plastoquinone pool, the cytochrome b6f complex, plastocyanin, PSI, ferredoxin, and finally to NADP+. Blocking PSII's electron transfer to plastoquinone with DCMU halts this entire pathway, stopping O2 evolution and NADPH production. Cyclic photophosphorylation, however, involves only PSI: light excites P700, electrons move to ferredoxin, are cycled back via PGR5/PGRL1 complexes to the plastoquinone pool, flow through cytochrome b6f to pump protons, and return to PSI via plastocyanin. This cycle does not depend on PSII or water splitting, so it can continue in the presence of DCMU, allowing some proton pumping and ATP synthesis without net NADPH or O2 production.
Q187. Cyanide irreversibly binds to the iron center of cytochrome c oxidase (Complex IV), blocking electron transfer to oxygen. Which of the following correctly describes the sequence of metabolic consequences in a cell exposed to cyanide?
When Complex IV is blocked, electrons cannot be passed to O2. The entire electron transport chain backs up: ubiquinol accumulates in a reduced state, and upstream complexes cannot pump protons because electron flow has stopped. The proton gradient dissipates through normal proton leakage but is no longer replenished, halting ATP synthase. Without NAD+ and FAD regeneration by the ETC, NADH and FADH2 accumulate, product-inhibiting the dehydrogenases of the Krebs cycle and slowing it. Falling ATP and rising ADP transiently stimulate glycolysis via allosteric activation of PFK-1, though this compensation is limited by NAD+ availability. Choice C is incorrect: backed-up reduced carriers cannot force proton pumping because the electron flow that drives pumping has stopped, so the gradient would not increase.
Q188. In chloroplasts, the Calvin cycle enzyme fructose-1,6-bisphosphatase (FBPase) is inactivated by an intramolecular disulfide bond and activated when that bond is reduced by thioredoxin. Thioredoxin is reduced by ferredoxin, which receives electrons directly from Photosystem I. Which of the following best explains the regulatory logic of this thioredoxin system?
The thioredoxin system couples Calvin cycle enzyme activity directly to light availability through a redox signal cascade. When light is present, PSI reduces ferredoxin, which reduces thioredoxin, which in turn reduces and activates Calvin cycle enzymes including FBPase, sedoheptulose-1,7-bisphosphatase, and others. In darkness, ferredoxin is not reduced, thioredoxin remains oxidized, and the disulfide bonds in target enzymes are maintained, keeping them inactive. This elegant switch ensures that the Calvin cycle's energy-consuming reactions (which require ATP and NADPH) are activated precisely when the light reactions are providing those substrates, and are turned off in the dark to prevent futile consumption of carbohydrate reserves.
Q189. RuBisCO has an approximate Km for CO2 of 9 µM and a Km for O2 of 535 µM. In a typical illuminated mesophyll cell, dissolved stromal CO2 is approximately 8 µM and dissolved O2 is approximately 250 µM. Which of the following conclusions about RuBisCO activity is best supported by these values?
At the Km, an enzyme operates at exactly half its maximum velocity. With stromal CO2 at approximately 8 µM (just below the Km of 9 µM), RuBisCO's carboxylase activity is near but below half-maximal — well below Vmax and highly sensitive to CO2 fluctuations. With O2 at approximately 250 µM (roughly half the Km of 535 µM), oxygenase activity is also below half-maximal but still substantial enough to drive significant photorespiration under normal atmospheric conditions. Choice D incorrectly concludes that oxygenase activity is negligible below the Km: enzyme activity exists across all substrate concentrations (activity is half-maximal at Km, not zero). The observed extent of photorespiration in C3 plants is consistent with these kinetic parameters — both activities are substrate-limited and occur simultaneously.
Q190. An organism capable of aerobic respiration switches to lactic acid fermentation when O2 is depleted. Aerobic respiration yields approximately 30 ATP per glucose while fermentation yields only 2 ATP. Which of the following best explains why fermentation is thermodynamically possible despite its dramatically lower efficiency?
The overall conversion of glucose to lactate is exergonic (delta G is negative), so fermentation is thermodynamically spontaneous. The specific reaction catalyzed by lactate dehydrogenase — reduction of pyruvate to lactate using NADH — is also exergonic (delta G approximately -25 kJ/mol) and serves a critical metabolic function: it regenerates NAD+ from NADH. NAD+ is required as the electron acceptor at the glyceraldehyde-3-phosphate dehydrogenase step of glycolysis; without NAD+ regeneration, glycolysis would halt entirely and no ATP would be produced. The 2 ATP from glycolysis represent partial capture of glucose's free energy under anaerobic conditions. Choice C is incorrect because pyruvate reduction to lactate is exergonic, not endergonic. Choice D is incorrect because glucose oxidation is spontaneous and requires no external ATP input to initiate.
Q191. Which bond in an ATP molecule is broken to release energy for most cellular work?
ATP hydrolysis most commonly cleaves the terminal phosphoanhydride bond between the beta and gamma phosphate groups, releasing inorganic phosphate (Pi) and ADP along with approximately 7.3 kcal/mol of free energy under standard conditions. This bond is particularly unstable due to electrostatic repulsion among the negatively charged phosphate groups. Choice C is incorrect because N-glycosidic bonds link nitrogenous bases to sugars in nucleotides and nucleic acids but are not the energy-releasing bonds in ATP hydrolysis.
Q192. What are the net products of glycolysis for each molecule of glucose?
Glycolysis converts one 6-carbon glucose into two 3-carbon pyruvate molecules. Although 4 ATP are produced, 2 ATP are consumed in the energy-investment phase, yielding a net gain of 2 ATP. Two NAD+ molecules are reduced to NADH. No CO2 is released during glycolysis, and FADH2 is not a glycolytic product — FADH2 is produced in the Krebs cycle. Acetyl-CoA is generated during pyruvate oxidation in the mitochondrial matrix, which occurs after glycolysis.
Q193. Which wavelengths of visible light does chlorophyll a absorb most strongly?
Chlorophyll a has two major absorption peaks: one in the blue-violet region near 430 nm and one in the red region near 680 nm. Light at these wavelengths drives photosynthesis most efficiently. Green and yellow wavelengths (choice B) are poorly absorbed and largely reflected, which is why most plants appear green to our eyes. Far-red and ultraviolet light (choice D) are outside the main absorption range of chlorophyll a.
Q194. A researcher treats isolated mitochondria with a chemical that makes the inner mitochondrial membrane freely permeable to H+ ions. Which of the following would most likely result?
ATP synthase (Complex V) uses the electrochemical proton gradient across the inner mitochondrial membrane — the proton-motive force — to drive ATP synthesis via chemiosmosis. If H+ ions can leak freely across the membrane, the gradient is dissipated without passing through ATP synthase, so ATP synthesis drops dramatically. The electron transport chain itself does not require the gradient to function; it simply transfers electrons to O2 and pumps protons as a byproduct. Without back-pressure from the gradient, ETC activity may actually increase. Choice B is wrong because bypassing ATP synthase eliminates, rather than increases, ATP production.
Q195. Which of the following correctly distinguishes substrate-level phosphorylation from oxidative phosphorylation?
In substrate-level phosphorylation, an enzyme catalyzes the direct transfer of a phosphate group from a high-energy substrate (such as phosphoenolpyruvate in glycolysis or succinyl-CoA in the Krebs cycle) to ADP, forming ATP without a membrane potential. Oxidative phosphorylation, by contrast, uses the proton-motive force generated by the electron transport chain to power ATP synthase. Choice B reverses the oxygen requirements — oxidative phosphorylation requires O2 as the terminal electron acceptor, while substrate-level phosphorylation does not. Choice D is incorrect because oxidative phosphorylation generates the vast majority (~32 of ~36 net ATP) per glucose.
Q196. A plant is exposed to monochromatic light of exactly 700 nm. Which of the following would most likely occur in the chloroplasts?
Photosystem I contains the reaction center P700, named for its absorption peak at 700 nm, while Photosystem II contains P680 with a peak near 680 nm. At 700 nm, PS I is preferentially excited. In noncyclic electron flow, PSII must provide electrons to replace those excited out of PSI; without PSII activation and the water-splitting reaction, the supply of electrons to PSI is limiting. The plant could shift to cyclic photophosphorylation under such conditions but cannot sustain full noncyclic flow. Choice C is incorrect because PSII, not PSI, absorbs maximally near 680 nm.
Q197. During intense exercise, human skeletal muscle cells convert pyruvate to lactate. What is the primary metabolic function of this reaction?
When O2 is insufficient for the electron transport chain to reoxidize NADH, NAD+ becomes limiting in the cytosol. Without NAD+, glycolysis cannot proceed because the glyceraldehyde-3-phosphate dehydrogenase step requires it. The reduction of pyruvate to lactate by lactate dehydrogenase regenerates NAD+, allowing glycolysis to continue and maintain ATP production. No ATP is produced in this step itself — choice B is incorrect. Choice D is also incorrect because lactate is exported to the liver (Cori cycle) rather than oxidized directly by the muscle cell that produced it.
Q198. Dinitrophenol (DNP) is a lipid-soluble compound that shuttles H+ ions across the inner mitochondrial membrane independently of ATP synthase. In cells treated with DNP, which outcome would be expected?
DNP is a classical uncoupler: it dissipates the proton-motive force by carrying H+ across the inner mitochondrial membrane as heat rather than channeling them through ATP synthase. With the gradient depleted, ATP synthase activity falls sharply. The electron transport chain, however, is not directly inhibited — it continues (and may accelerate) because the lack of back-pressure from a large gradient allows electrons to flow more rapidly to O2, increasing O2 consumption. The net result is high metabolic rate with low ATP production, manifesting as heat generation. This mechanism explains why DNP was historically (and dangerously) misused as a weight-loss agent.
Q199. When NADP+ becomes limiting because the stroma already contains abundant NADPH, chloroplasts can switch from noncyclic to cyclic photophosphorylation. Which of the following correctly describes the outcome of cyclic photophosphorylation?
In cyclic photophosphorylation, electrons excited from Photosystem I (P700) are passed to ferredoxin and then cycled back through the cytochrome b6f complex to plastocyanin and back to PSI, rather than reducing NADP+. This electron cycling pumps additional H+ ions across the thylakoid membrane, generating a proton gradient that drives ATP synthesis. Because PSII is not involved, water is not split and neither O2 nor NADPH is produced. Cyclic flow therefore adjusts the ATP-to-NADPH ratio upward when extra ATP is needed for the Calvin cycle. Choice C is incorrect because PSII and water-splitting are not part of cyclic electron flow.
Q200. Phosphofructokinase-1 (PFK-1), the committed-step enzyme of glycolysis, is allosterically inhibited by ATP and citrate and activated by AMP and ADP. In which of the following cellular states would PFK-1 activity be greatest?
PFK-1 is the primary control point of glycolysis and acts as an energy sensor. High AMP signals a low cellular energy charge, strongly activating PFK-1 to accelerate ATP production through glycolysis. When O2 is depleted, the electron transport chain slows, ATP synthesis drops, and adenylate kinase converts two ADP to ATP plus AMP, rapidly raising AMP levels. Simultaneously, citrate (a Krebs cycle intermediate and signal of biosynthetic sufficiency) is low because the Krebs cycle is also slowed. This combination of high AMP and low citrate provides maximal PFK-1 activation. Choices B, C, and D all describe high-energy states with elevated ATP and citrate, which inhibit PFK-1 to prevent unnecessary glycolytic flux.
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This unit covers photosynthesis, cell respiration and ATP cycle — essential concepts for AP Biology. Use our interactive study games to test your understanding, or review questions in traditional format below.
- Photosynthesis
- Cell respiration
- Atp cycle
Key Concepts Breakdown
1 Photosynthesis
Photosynthesis converts light energy into chemical energy stored as glucose, occurring in two stages: the light-dependent reactions (thylakoid membranes) and the Calvin cycle (stroma). Students must know the inputs, outputs, and location of each stage, as well as how changes in environmental conditions affect the rate of photosynthesis.
Key Points
- Light reactions split water (photolysis), produce ATP and NADPH, and release O2 as a byproduct; occurs in thylakoid membranes
- Calvin cycle uses ATP and NADPH to fix CO2 into G3P via RuBisCO; 3 CO2 → 1 net G3P; occurs in stroma
- The overall equation: 6CO2 + 6H2O + light energy → C6H12O6 + 6O2
- Limiting factors include light intensity, CO2 concentration, and temperature — each affects the rate of a specific stage
A plant is placed in a sealed chamber with water and exposed to increasing light intensity. At low light, the rate of O2 production is proportional to light intensity. At high light intensity, O2 production plateaus even as light increases. What is the most likely limiting factor at high light intensity?
At low light, photons are limiting, so more light directly increases the rate of the light reactions and O2 production. Once light is saturating, the Calvin cycle becomes the bottleneck because ATP and NADPH are produced faster than RuBisCO can fix CO2. The plateau indicates that CO2 concentration or enzyme availability (not light) is now the limiting factor.
2 Cellular Respiration
Cellular respiration breaks down glucose to produce ATP through three interconnected stages: glycolysis (cytoplasm), the Krebs cycle (mitochondrial matrix), and oxidative phosphorylation via the electron transport chain (inner mitochondrial membrane). Students must know the net ATP yield per stage, the role of electron carriers (NADH, FADH2), and how the process differs under aerobic vs. anaerobic conditions.
Key Points
- Glycolysis: 1 glucose → 2 pyruvate, net 2 ATP, 2 NADH; occurs in cytoplasm; does not require O2
- Krebs cycle: each acetyl-CoA yields 3 NADH, 1 FADH2, 1 ATP (GTP); run twice per glucose; occurs in mitochondrial matrix
- ETC and chemiosmosis: NADH and FADH2 donate electrons; proton gradient drives ATP synthase; O2 is the final electron acceptor; ~32-34 ATP produced
- Fermentation (anaerobic): regenerates NAD+ to keep glycolysis running; yields only 2 ATP net (lactic acid or ethanol + CO2)
A researcher adds a chemical that makes the inner mitochondrial membrane freely permeable to H+ ions. Predict the effect on ATP production and explain which stage(s) are affected.
The chemical eliminates the proton gradient across the inner mitochondrial membrane by allowing H+ to leak back without passing through ATP synthase. Without the gradient, chemiosmosis cannot drive ATP synthesis, so oxidative phosphorylation produces no ATP. Glycolysis and the Krebs cycle are unaffected and continue producing small amounts of ATP directly (substrate-level phosphorylation), but total ATP yield drops dramatically from ~36-38 to only ~4 ATP per glucose.
3 ATP Cycle
ATP (adenosine triphosphate) is the universal energy currency of the cell, coupling energy-releasing (catabolic) reactions to energy-requiring (anabolic) reactions through the continuous cycle of ATP hydrolysis and regeneration. Students must understand the structure of ATP, how hydrolysis releases free energy, and how that energy drives cellular work.
Key Points
- ATP hydrolysis: ATP + H2O → ADP + Pi + ~7.3 kcal/mol free energy; energy released drives endergonic reactions
- ATP is regenerated from ADP + Pi using energy from cellular respiration (and photosynthesis in plants)
- ATP is used for three types of cellular work: mechanical (muscle contraction), transport (active transport pumps), and chemical (biosynthesis)
- ATP is not stored in large quantities; cells continuously recycle ADP → ATP; a human cell may recycle its ATP hundreds of times per day
The sodium-potassium pump moves 3 Na+ out and 2 K+ into a cell per cycle, against their concentration gradients, consuming 1 ATP per cycle. If this pump is given an inhibitor that blocks ATP hydrolysis, predict two downstream cellular effects.
Without ATP hydrolysis, the pump cannot change conformation and transport ions, so the Na+/K+ gradient collapses — intracellular Na+ rises and K+ falls. First, the resting membrane potential depolarizes because the electrochemical gradient that sustains it is lost, impairing nerve and muscle signaling. Second, because many secondary active transporters rely on the Na+ gradient as a driving force, glucose uptake and other coupled transport processes also fail, starving the cell of substrates for ATP synthesis.
Questions, answered.
What is Cellular Energetics?
Cellular Energetics is Unit 3 of AP Biology, covering photosynthesis, cell respiration and ATP cycle.
How to study for AP Biology Unit 3?
Start with the Quick Summary above, review the Key Concepts, then test yourself with our interactive study games. Aim for 80%+ accuracy before moving on.
How many questions are in this unit?
This unit has 200 review questions, each with a written explanation, playable across 5 different game modes or readable in plain-text mode.